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| 1 |
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| Inshallah we'll start numerical descriptive measures |
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| 2 |
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| for the population. Last time we talked about the |
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| 3 |
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| same measures. I mean the same descriptive measures |
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| 4 |
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| for a sample. And we have already talked about the |
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| 5 |
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| mean, variance, and standard deviation. These are |
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| 6 |
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| called statistics because they are computed from |
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| 7 |
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| the sample. Here we'll see how can we do the same |
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| 8 |
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| measures but for a population, I mean for the |
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| 9 |
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| entire dataset. So descriptive statistics |
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| 10 |
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| described previously in the last two lectures was |
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| 11 |
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| for a sample. Here we'll just see how can we |
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| 12 |
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| compute these measures for the entire population. |
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| 13 |
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| In this case, the statistics we talked about |
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| 14 |
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| before are called And if you remember the first |
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| 15 |
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| lecture, we said there is a difference between |
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| 16 |
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| statistics and parameters. A statistic is a value |
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| 17 |
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| that computed from a sample, but parameter is a |
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| 18 |
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| value computed from population. So the important |
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| 19 |
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| population parameters are population mean, |
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| 20 |
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| variance, and standard deviation. Let's start with |
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| 21 |
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| the first one, the mean, or the population mean. |
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| 22 |
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| As the sample mean is defined by the sum of the |
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| 23 |
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| values divided by the sample size. But here, we |
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| 24 |
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| have to divide by the population size. So that's |
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| the difference between sample mean and population |
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| 26 |
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| mean. For the sample mean, we use x bar. Here we |
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| 27 |
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| use Greek letter, mu. This is pronounced as mu. So |
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| 28 |
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| mu is the sum of the x values divided by the |
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| 29 |
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| population size, not the sample size. So it's |
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| 30 |
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| quite similar to the sample mean. So mu is the |
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| 31 |
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| population mean, n is the population size, and xi |
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| 32 |
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| is the ith value of the variable x. Similarly, for |
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| the other parameter, which is the variance, the |
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| 34 |
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| variance There is a little difference between the |
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| 35 |
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| sample and population variance. Here, we subtract |
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| 36 |
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| the population mean instead of the sample mean. So |
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| 37 |
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| sum of xi minus mu squared, then divide by this |
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| 38 |
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| population size, capital N, instead of N minus 1. |
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| 39 |
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| So that's the difference between sample and |
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| 40 |
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| population variance. So again, in the sample |
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| 41 |
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| variance, we subtracted x bar. Here, we subtract |
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| 42 |
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| the mean of the population, mu, then divide by |
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| 43 |
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| capital N instead of N minus 1. So the |
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| 44 |
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| computations for the sample and the population |
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| 45 |
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| mean or variance are quite similar. Finally, the |
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| 46 |
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| population standard deviation. is the same as the |
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| 47 |
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| sample population variance and here just take the |
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| 48 |
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| square root of the population variance and again |
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| 49 |
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| as we did as we explained before the standard |
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| 50 |
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| deviation has the same units as the original unit |
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| 51 |
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| so nothing is new we just extend the sample |
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| 52 |
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| statistic to the population parameter and again |
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| 53 |
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| The mean is denoted by mu, it's a Greek letter. |
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| 54 |
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| The population variance is denoted by sigma |
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| 55 |
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| squared. And finally, the population standard |
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| 56 |
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| deviation is denoted by sigma. So that's the |
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| 57 |
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| numerical descriptive measures either for a sample |
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| 58 |
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| or a population. So just summary for these |
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| 59 |
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| measures. The measures are mean variance, standard |
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| 60 |
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| deviation. Population parameters are mu for the |
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| 61 |
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| mean, sigma squared for variance, and sigma for |
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| 62 |
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| standard deviation. On the other hand, for the |
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| 63 |
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| sample statistics, we have x bar for sample mean, |
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| 64 |
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| s squared for the sample variance, and s is the |
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| 65 |
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| sample standard deviation. That's sample |
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| 66 |
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| statistics against population parameters. Any |
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| 67 |
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| question? |
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| 68 |
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| Let's move to a new topic, which is empirical rule. |
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| 69 |
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| Now, empirical rule is just we |
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| 70 |
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| have to approximate the variation of data in case |
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| 71 |
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| of They'll shift. I mean suppose the data is |
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| 72 |
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| symmetric around the mean. I mean by symmetric |
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| 73 |
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| around the mean, the mean is the vertical line |
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| 74 |
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| that splits the data into two halves. One to the |
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| 75 |
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| right and the other to the left. I mean, the mean, |
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| 76 |
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| the area to the right of the mean equals 50%, |
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| 77 |
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| which is the same as the area to the left of the |
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| 78 |
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| mean. Now suppose or consider the data is bell |
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| 79 |
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| -shaped. Bell-shaped, normal, or symmetric? So |
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| 80 |
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| it's not skewed either to the right or to the |
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| 81 |
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| left. So here we assume, okay, the data is bell |
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| 82 |
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| -shaped. In this scenario, in this case, there is |
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| 83 |
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| a rule called 68, 95, 99.7 rule. Number one, |
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| 84 |
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| approximately 68% of the data in a bell-shaped |
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| 85 |
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| lies within one standard deviation of the |
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| 86 |
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| population. So this is the first rule, 68% of the |
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| 87 |
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| data or of the observations Lie within a mu minus |
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| 88 |
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| sigma and a mu plus sigma. That's the meaning of |
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| 89 |
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| the data in a bell-shaped distribution is within one |
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| 90 |
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| standard deviation of mean or mu plus or minus |
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| 91 |
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| sigma. So again, you can say that if the data is |
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| 92 |
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| normally distributed or if the data is bell |
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| 93 |
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| shaped, that is 68% of the data lies within one |
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| 94 |
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| standard deviation of the mean, either below or |
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| 95 |
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| above it. So 68% of the data. So this is the first |
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| 96 |
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| rule. |
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| 97 |
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| 68% of the data lies between mu minus sigma and mu |
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| 98 |
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| plus sigma. |
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| 99 |
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| The other rule is approximately 95% of the data in |
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| 100 |
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| a bell-shaped distribution lies within two |
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| 101 |
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| standard deviations of the mean. That means this |
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| 102 |
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| area covers between minus two sigma and plus mu |
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| 103 |
| 00:08:00,880 --> 00:08:08,360 |
| plus two sigma. So 95% of the data lies between |
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| 104 |
| 00:08:08,360 --> 00:08:15,410 |
| minus mu two sigma And finally, |
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| 105 |
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| approximately 99.7% of the data, it means almost |
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| 106 |
| 00:08:21,270 --> 00:08:25,490 |
| the data. Because we are saying 99.7 means most of |
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| 107 |
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| the data falls or lies within three standard |
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| 108 |
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| deviations of the mean. So 99.7% of the data lies |
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| 109 |
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| between mu minus the pre-sigma and the mu plus of |
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| 110 |
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| pre-sigma. |
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| 111 |
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| 68, 95, 99.7 are fixed numbers. Later in chapter |
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| 112 |
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| 6, we will explain in details other coefficients. |
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| 113 |
| 00:08:55,530 --> 00:08:58,250 |
| Maybe suppose we are interested not in one of |
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| 114 |
| 00:08:58,250 --> 00:09:03,010 |
| these. Suppose we are interested in 90% or 80% or |
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| 115 |
| 00:09:03,010 --> 00:09:11,500 |
| 85%. This rule just for 689599.7. This rule is |
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| 116 |
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| called 689599 |
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| 117 |
| 00:09:15,560 --> 00:09:22,960 |
| .7 rule. That is, again, 68% of the data lies |
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| 118 |
| 00:09:22,960 --> 00:09:27,030 |
| within one standard deviation of the mean. 95% of |
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| 119 |
| 00:09:27,030 --> 00:09:30,370 |
| the data lies within two standard deviations of |
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| 120 |
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| the mean. And finally, most of the data falls |
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| 121 |
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| within three standard deviations of the mean. |
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| 122 |
| 00:09:39,870 --> 00:09:43,330 |
| Let's see how can we use this empirical rule for a |
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| 123 |
| 00:09:43,330 --> 00:09:49,850 |
| specific example. Imagine that the variable math |
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| 124 |
| 00:09:49,850 --> 00:09:54,070 |
| test scores is bell shaped. So here we assume that |
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| 125 |
| 00:09:55,230 --> 00:10:00,950 |
| The math test score has symmetric shape or bell |
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| 126 |
| 00:10:00,950 --> 00:10:04,230 |
| shape. In this case, we can use the previous rule. |
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| 127 |
| 00:10:04,350 --> 00:10:09,610 |
| Otherwise, we cannot. So assume the math test |
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| 128 |
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| score is bell-shaped with a mean of 500. I mean, |
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| 129 |
| 00:10:16,410 --> 00:10:19,750 |
| the population mean is 500 and standard deviation |
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| 130 |
| 00:10:19,750 --> 00:10:24,620 |
| of 90. And let's see how can we apply the |
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| 131 |
| 00:10:24,620 --> 00:10:29,220 |
| empirical rule. So again, meta score has a mean of |
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| 132 |
| 00:10:29,220 --> 00:10:35,300 |
| 500 and standard deviation sigma is 90. Then we |
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| 133 |
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| can say that 60% of all test takers scored between |
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| 134 |
| 00:10:43,200 --> 00:10:46,640 |
| 68%. |
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| 135 |
| 00:10:46,640 --> 00:10:56,550 |
| So mu is 500. minus sigma is 90. And mu plus |
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| 136 |
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| sigma, 500 plus 90. So you can say that 68% or 230 |
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| 137 |
| 00:11:05,390 --> 00:11:15,610 |
| of all test takers scored between 410 and 590. So |
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| 138 |
| 00:11:15,610 --> 00:11:22,900 |
| 68% of all test takers who took that exam scored |
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| 139 |
| 00:11:22,900 --> 00:11:27,740 |
| between 14 and 590. That if we assume previously |
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| 140 |
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| the data is well shaped, otherwise we cannot say |
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| 141 |
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| that. For the other rule, 95% of all test takers |
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| 142 |
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| scored between mu is 500 minus 2 times sigma, 500 |
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| 143 |
| 00:11:44,400 --> 00:11:49,760 |
| plus 2 times sigma. So that means 500 minus 180 is |
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| 144 |
| 00:11:49,760 --> 00:11:55,100 |
| 320. 500 plus 180 is 680. So you can say that |
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| 145 |
| 00:11:55,100 --> 00:11:59,080 |
| approximately 95% of all test takers scored |
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| 146 |
| 00:11:59,080 --> 00:12:07,860 |
| between 320 and 680. Finally, you can say that |
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| 147 |
| 00:12:10,770 --> 00:12:13,570 |
| all of the test takers, approximately all, because |
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| 148 |
| 00:12:13,570 --> 00:12:20,030 |
| when we are saying 99.7 it means just 0.3 is the |
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| 149 |
| 00:12:20,030 --> 00:12:23,590 |
| rest, so you can say approximately all test takers |
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| 150 |
| 00:12:23,590 --> 00:12:30,730 |
| scored between mu minus three sigma which is 90 |
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| 151 |
| 00:12:30,730 --> 00:12:39,830 |
| and mu It lost 3 seconds. So 500 minus 3 times 9 |
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| 152 |
| 00:12:39,830 --> 00:12:45,950 |
| is 270. So that's 230. 500 plus 270 is 770. So we |
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| 153 |
| 00:12:45,950 --> 00:12:49,690 |
| can say that 99.7% of all the stackers scored |
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| 154 |
| 00:12:49,690 --> 00:12:55,610 |
| between 230 and 770. I will give another example |
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| 155 |
| 00:12:55,610 --> 00:12:59,210 |
| just to make sure that you understand the meaning |
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| 156 |
| 00:12:59,210 --> 00:13:00,870 |
| of this rule. |
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| 157 |
| 00:13:03,620 --> 00:13:09,720 |
| For business, a statistic goes. |
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| 158 |
| 00:13:15,720 --> 00:13:20,720 |
| For business, a statistic example. Suppose the |
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| 159 |
| 00:13:20,720 --> 00:13:29,740 |
| scores are bell-shaped. So we are assuming the |
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| 160 |
| 00:13:29,740 --> 00:13:40,970 |
| data is bell-shaped. with a mean of 75 and standard |
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| 161 |
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| deviation of 5. |
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| 162 |
| 00:13:44,990 --> 00:13:53,810 |
| Also, let's assume that 100 students took |
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| 163 |
| 00:13:53,810 --> 00:14:00,840 |
| the exam. So we have 100 students. Last year took |
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| 164 |
| 00:14:00,840 --> 00:14:05,360 |
| the exam of business statistics. The mean was 75. |
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| 165 |
| 00:14:06,240 --> 00:14:10,920 |
| And standard deviation was 5. And let's see how it |
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| 166 |
| 00:14:10,920 --> 00:14:17,100 |
| can tell about the 68% rule. It means that 68% |
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| 167 |
| 00:14:17,100 --> 00:14:22,100 |
| of all the students scored |
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| 168 |
| 00:14:22,100 --> 00:14:28,650 |
| between mu minus sigma. Mu is 75. minus sigma and |
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| 169 |
| 00:14:28,650 --> 00:14:29,610 |
| the mu plus sigma. |
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| 170 |
| 00:14:33,590 --> 00:14:39,290 |
| So that means 68 students, because we have 100, so |
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| 171 |
| 00:14:39,290 --> 00:14:45,410 |
| you can say 68 students scored between 70 and 80. |
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| 172 |
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| So 68 students out of 100 scored between 70 and |
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| 173 |
| 00:14:53,290 --> 00:15:02,990 |
| 80. About 95 students out of 100 scored between 75 |
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| 174 |
| 00:15:02,990 --> 00:15:12,190 |
| minus 2 times 5. 75 plus 2 times 5. So that gives |
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| 175 |
| 00:15:12,190 --> 00:15:13,770 |
| 65. |
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| 176 |
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| The minimum and the maximum is 85. So you can say |
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| 177 |
| 00:15:20,950 --> 00:15:25,930 |
| that around 95 students scored between 65 and 85. |
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| 178 |
| 00:15:26,650 --> 00:15:33,510 |
| Finally, maybe you can see all students. Because |
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| 179 |
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| when you're saying 99.7, it means almost all the |
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| 180 |
| 00:15:38,650 --> 00:15:47,210 |
| students scored between 75 minus 3 times Y. and 75 |
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| 181 |
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| plus three times one. So that's 6 days in two |
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| 182 |
| 00:15:52,970 --> 00:15:59,150 |
| nights. Now let's look carefully at these three |
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| 183 |
| 00:15:59,150 --> 00:16:04,910 |
| intervals. The first one is seven to eight, the |
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| 184 |
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| other one 65 to 85, then 6 to 90. When we are |
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| 185 |
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| more confident, |
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| 186 |
| 00:16:15,170 --> 00:16:20,630 |
| When we are more confident here for 99.7%, the |
|
|
| 187 |
| 00:16:20,630 --> 00:16:25,930 |
| interval becomes wider. So this is the widest |
|
|
| 188 |
| 00:16:25,930 --> 00:16:31,430 |
| interval. Because here, the length of the interval |
|
|
| 189 |
| 00:16:31,430 --> 00:16:37,090 |
| is around 10. The other one is 20. |
|
|
| 223 |
| 00:19:32,970 --> 00:19:36,370 |
| falls within two standard ratios. That if the data |
|
|
| 224 |
| 00:19:36,370 --> 00:19:39,350 |
| is bell shaped. Now what's about if the data is |
|
|
| 225 |
| 00:19:39,350 --> 00:19:43,210 |
| not bell shaped? We have to use the shape-shape rule. |
|
|
| 226 |
| 00:19:43,830 --> 00:19:51,170 |
| So 1 minus 1 over k is 2. So 2, 2, 2 squared. So 1 |
|
|
| 227 |
| 00:19:51,170 --> 00:19:58,130 |
| minus 1 fourth. That gives. three quarters, I |
|
|
| 228 |
| 00:19:58,130 --> 00:20:03,370 |
| mean, 75%. So instead of saying 95% of the data |
|
|
| 229 |
| 00:20:03,370 --> 00:20:06,850 |
| lies within one or two standard deviations of the |
|
|
| 230 |
| 00:20:06,850 --> 00:20:13,070 |
| mean, if the data is bell-shaped, if the data is |
|
|
| 231 |
| 00:20:13,070 --> 00:20:17,590 |
| not bell-shaped, you have to say that 75% of the |
|
|
| 232 |
| 00:20:17,590 --> 00:20:22,190 |
| data falls within two standard deviations. For |
|
|
| 233 |
| 00:20:22,190 --> 00:20:26,570 |
| bell shape, you are 95% confident there. But here, |
|
|
| 234 |
| 00:20:27,190 --> 00:20:36,710 |
| you're just 75% confident. Suppose k is 3. Now for |
|
|
| 235 |
| 00:20:36,710 --> 00:20:41,110 |
| k equal 3, we said 99.7% of the data falls within |
|
|
| 236 |
| 00:20:41,110 --> 00:20:44,890 |
| three standard deviations. Now here, if the data |
|
|
| 237 |
| 00:20:44,890 --> 00:20:51,940 |
| is not bell shape, 1 minus 1 over k squared. 1 |
|
|
| 238 |
| 00:20:51,940 --> 00:20:56,540 |
| minus 1 |
|
|
| 239 |
| 00:20:56,540 --> 00:21:00,760 |
| over 3 squared is one-ninth. One-ninth is 0.11. 1 |
|
|
| 240 |
| 00:21:00,760 --> 00:21:06,440 |
| minus 0.11 means 89% of the data, instead of |
|
|
| 241 |
| 00:21:06,440 --> 00:21:13,900 |
| saying 99.7. So 89% of the data will fall within |
|
|
| 242 |
| 00:21:13,900 --> 00:21:16,460 |
| three standard deviations of the population mean. |
|
|
| 243 |
| 00:21:18,510 --> 00:21:22,610 |
| regardless of how the data are distributed around |
|
|
| 244 |
| 00:21:22,610 --> 00:21:26,350 |
| them. So here, we have two scenarios. One, if the |
|
|
| 245 |
| 00:21:26,350 --> 00:21:29,390 |
| data is symmetric, which is called the empirical rule |
|
|
| 246 |
| 00:21:29,390 --> 00:21:34,710 |
| 68959917. And the other one is called the shape-by |
|
|
| 247 |
| 00:21:34,710 --> 00:21:38,370 |
| -shape rule, and that regardless of the shape of |
|
|
| 248 |
| 00:21:38,370 --> 00:21:38,710 |
| the data. |
|
|
| 249 |
| 00:21:41,890 --> 00:21:49,210 |
| Excuse me? Yes. In this case, you don't know the |
|
|
| 250 |
| 00:21:49,210 --> 00:21:51,490 |
| distribution of the data. And the reality is |
|
|
| 251 |
| 00:21:51,490 --> 00:21:58,650 |
| sometimes the data has an unknown distribution. For |
|
|
| 252 |
| 00:21:58,650 --> 00:22:02,590 |
| this reason, we have to use chip-chip portions. |
|
|
| 253 |
| 00:22:05,410 --> 00:22:09,830 |
| That's all for the empirical rule and the chip-chip rule. |
|
|
| 254 |
| 00:22:11,230 --> 00:22:18,150 |
| The next topic is quartile measures. So far, we |
|
|
| 255 |
| 00:22:18,150 --> 00:22:24,330 |
| have discussed central tendency measures, and we |
|
|
| 256 |
| 00:22:24,330 --> 00:22:28,450 |
| have talked about mean, median, and more. Then we |
|
|
| 257 |
| 00:22:28,450 --> 00:22:32,830 |
| moved to location of variability or spread or |
|
|
| 258 |
| 00:22:32,830 --> 00:22:37,810 |
| dispersion. And we talked about range, variance, |
|
|
| 259 |
| 00:22:37,950 --> 00:22:38,890 |
| and standardization. |
|
|
| 260 |
| 00:22:41,570 --> 00:22:48,230 |
| And we said that outliers affect the mean much |
|
|
| 261 |
| 00:22:48,230 --> 00:22:51,470 |
| more than the median. And also, outliers affect |
|
|
| 262 |
| 00:22:51,470 --> 00:22:55,730 |
| the range. Here, we'll talk about other measures |
|
|
| 263 |
| 00:22:55,730 --> 00:22:59,570 |
| of the data, which is called quartile measures. |
|
|
| 264 |
| 00:23:01,190 --> 00:23:03,450 |
| Here, actually, we'll talk about two measures. |
|
|
| 265 |
| 00:23:04,270 --> 00:23:10,130 |
| The first one is called the first quartile, and the other |
|
|
| 266 |
| 00:23:10,130 --> 00:23:14,150 |
| one is the third quartile. So we have two measures, |
|
|
| 267 |
| 00:23:15,470 --> 00:23:26,030 |
| the first and the third quartile. Quartiles split the ranked |
|
|
| 268 |
| 00:23:26,030 --> 00:23:32,930 |
| data into four equal segments. I mean, these |
|
|
| 269 |
| 00:23:32,930 --> 00:23:37,190 |
| measures split the data you have into four equal |
|
|
| 270 |
| 00:23:37,190 --> 00:23:37,730 |
| parts. |
|
|
| 271 |
| 00:23:42,850 --> 00:23:48,690 |
| Q1 has 25% of the data fall below it. I mean 25% |
|
|
| 272 |
| 00:23:48,690 --> 00:23:56,410 |
| of the values lie below Q1. So it means 75% of the |
|
|
| 273 |
| 00:23:56,410 --> 00:24:04,410 |
| values are above it. So 25 below and 75 above. But you |
|
|
| 274 |
| 00:24:04,410 --> 00:24:07,370 |
| have to be careful that the data is arranged from |
|
|
| 275 |
| 00:24:07,370 --> 00:24:12,430 |
| smallest to largest. So in this case, Q1 is a |
|
|
| 276 |
| 00:24:12,430 --> 00:24:19,630 |
| value that has 25% below it. So Q2 is called the |
|
|
| 277 |
| 00:24:19,630 --> 00:24:22,450 |
| median. The median, the value in the middle when |
|
|
| 278 |
| 00:24:22,450 --> 00:24:26,250 |
| we arrange the data from smallest to largest. So |
|
|
| 279 |
| 00:24:26,250 --> 00:24:31,190 |
| that means 50% of the data below and also 50% of |
|
|
| 280 |
| 00:24:31,190 --> 00:24:36,370 |
| the data above. The other measure is called |
|
|
| 281 |
| 00:24:36,370 --> 00:24:41,730 |
| the theoretical qualifying. In this case, we have 25% |
|
|
| 282 |
| 00:24:41,730 --> 00:24:47,950 |
| of the data above Q3 and 75% of the data below Q3. |
|
|
| 283 |
| 00:24:49,010 --> 00:24:54,410 |
| So quartiles split the ranked data into four equal |
|
|
| 284 |
| 00:24:54,410 --> 00:25:00,190 |
| segments, Q1 25% to the left, Q2 50% to the left, |
|
|
| 285 |
| 00:25:00,970 --> 00:25:08,590 |
| Q3 75% to the left, and 25% to the right. Before, |
|
|
| 286 |
| 00:25:09,190 --> 00:25:13,830 |
| we explained how to compute the median, and let's |
|
|
| 287 |
| 00:25:13,830 --> 00:25:18,850 |
| see how can we compute the first and third quartile. |
|
|
| 288 |
| 00:25:19,750 --> 00:25:23,650 |
| If you remember, when we computed the median, |
|
|
| 289 |
| 00:25:24,350 --> 00:25:28,480 |
| first we located the position of the median. And we |
|
|
| 290 |
| 00:25:28,480 --> 00:25:33,540 |
| said that the rank of n is odd. Yes, it was n plus |
|
|
| 291 |
| 00:25:33,540 --> 00:25:37,800 |
| 1 divided by 2. This is the location of the |
|
|
| 292 |
| 00:25:37,800 --> 00:25:41,100 |
| median, not the value. Sometimes the value may be |
|
|
| 293 |
| 00:25:41,100 --> 00:25:44,900 |
| equal to the location, but most of the time it's |
|
|
| 294 |
| 00:25:44,900 --> 00:25:48,340 |
| not. It's not the case. Now let's see how can we |
|
|
| 295 |
| 00:25:48,340 --> 00:25:54,130 |
| locate the fair support. The first quartile after |
|
|
| 296 |
| 00:25:54,130 --> 00:25:56,690 |
| you arrange the data from smallest to largest, the |
|
|
| 297 |
| 00:25:56,690 --> 00:26:01,290 |
| location is n plus 1 divided by 2. So that's the |
|
|
| 298 |
| 00:26:01,290 --> 00:26:06,890 |
| location of the first quartile. The median, as we |
|
|
| 299 |
| 00:26:06,890 --> 00:26:10,390 |
| mentioned before, is located in the middle. So it |
|
|
| 300 |
| 00:26:10,390 --> 00:26:15,210 |
| makes sense that if n is odd, the location of the |
|
|
| 301 |
| 00:26:15,210 --> 00:26:20,490 |
| median is n plus 1 over 2. Now, for the third |
|
|
| 302 |
| 00:26:20,490 --> 00:26:27,160 |
| quartile position, The location is N plus 1 |
|
|
| 303 |
| 00:26:27,160 --> 00:26:31,160 |
| divided by 4 times 3. So 3 times N plus 1 divided |
|
|
| 304 |
| 00:26:31,160 --> 00:26:39,920 |
| by 4. That's how can we locate Q1, Q2, and Q3. So |
|
|
| 305 |
| 00:26:39,920 --> 00:26:42,080 |
| one more time, the median, the value in the |
|
|
| 306 |
| 00:26:42,080 --> 00:26:46,260 |
| middle, and it's located exactly at the position N |
|
|
| 307 |
| 00:26:46,260 --> 00:26:52,590 |
| plus 1 over 2 for the ranked data. Q1 is located at |
|
|
| 308 |
| 00:26:52,590 --> 00:26:56,770 |
| n plus one divided by four. Q3 is located at the |
|
|
| 309 |
| 00:26:56,770 --> 00:26:59,670 |
| position three times n plus one divided by four. |
|
|
| 310 |
| 00:27:03,630 --> 00:27:07,490 |
| Now, when calculating the rank position, we can |
|
|
| 311 |
| 00:27:07,490 --> 00:27:14,690 |
| use one of these rules. First, if the result of |
|
|
| 312 |
| 00:27:14,690 --> 00:27:18,010 |
| the location, I mean, is a whole number, I mean, |
|
|
| 313 |
| 00:27:18,250 --> 00:27:24,050 |
| if it is an integer. Then the rank position is the |
|
|
| 314 |
| 00:27:24,050 --> 00:27:28,590 |
| same number. For example, suppose the rank |
|
|
| 315 |
| 00:27:28,590 --> 00:27:34,610 |
| position is four. So position number four is your |
|
|
| 316 |
| 00:27:34,610 --> 00:27:38,450 |
| quartile, either first or third or second |
|
|
| 317 |
| 00:27:38,450 --> 00:27:42,510 |
| quartile. So if the result is a whole number, then |
|
|
| 318 |
| 00:27:42,510 --> 00:27:48,350 |
| it is the rank position used. Now, if the result |
|
|
| 319 |
| 00:27:48,350 --> 00:27:52,250 |
| is a fractional half, I mean if the right position |
|
|
| 320 |
| 00:27:52,250 --> 00:27:58,830 |
| is 2.5, 3.5, 4.5. In this case, average the two |
|
|
| 321 |
| 00:27:58,830 --> 00:28:02,050 |
| corresponding data values. For example, if the |
|
|
| 322 |
| 00:28:02,050 --> 00:28:10,170 |
| right position is 2.5. So the rank position is 2 |
|
|
| 323 |
| 00:28:10,170 --> 00:28:13,210 |
| .5. So take the average of the corresponding |
|
|
| 324 |
| 00:28:13,210 --> 00:28:18,950 |
| values for the rank 2 and 3. So look at the value. |
|
|
| 325 |
| 00:28:19,280 --> 00:28:24,740 |
| at rank 2, value at rank 3, then take the average |
|
|
| 326 |
| 00:28:24,740 --> 00:28:29,300 |
| of the corresponding values. That if the rank |
|
|
| 327 |
| 00:28:29,300 --> 00:28:31,280 |
| position is fractional. |
|
|
| 328 |
| 00:28:34,380 --> 00:28:37,900 |
| So if the result is a whole number, just take it as |
|
|
| 329 |
| 00:28:37,900 --> 00:28:41,160 |
| it is. If it is a fractional half, take the |
|
|
| 330 |
| 00:28:41,160 --> 00:28:44,460 |
| corresponding data values and take the average of |
|
|
| 331 |
| 00:28:44,460 --> 00:28:49,110 |
| these two values. Now, if the result is not a |
|
|
| 332 |
| 00:28:49,110 --> 00:28:53,930 |
| whole number or a fraction of it. For example, |
|
|
| 333 |
| 00:28:54,070 --> 00:29:01,910 |
| suppose the location is 2.1. So the position is 2, |
|
|
| 334 |
| 00:29:02,390 --> 00:29:06,550 |
| just round up to the nearest integer. So that's |
|
|
| 335 |
| 00:29:06,550 --> 00:29:11,350 |
| 2. What's about if the position rank is 2.6? Just |
|
|
| 336 |
| 00:29:11,350 --> 00:29:16,060 |
| rank up to 3. So that's 3. So that's the rule you |
|
|
| 337 |
| 00:29:16,060 --> 00:29:21,280 |
| have to follow if the result is a number, a whole |
|
|
| 338 |
| 00:29:21,280 --> 00:29:27,200 |
| number, I mean integer, fraction of half, or not |
|
|
| 339 |
| 00:29:27,200 --> 00:29:31,500 |
| a real number, I mean, not whole number, or fraction |
|
|
| 340 |
| 00:29:31,500 --> 00:29:35,540 |
| of half. Look at this specific example. Suppose we |
|
|
| 341 |
| 00:29:35,540 --> 00:29:40,180 |
| have this data. This is an ordered array, 11, 12, up |
|
|
| 342 |
| 00:29:40,180 --> 00:29:45,680 |
| to 22. And let's see how can we compute these |
|
|
| 343 |
| 00:29:45,680 --> 00:29:46,240 |
| measures. |
|
|
| 344 |
| 00:29:50,080 --> 00:29:51,700 |
| Look carefully here. |
|
|
| 345 |
| 00:29:55,400 --> 00:29:59,260 |
| First, let's compute the median. The median is |
|
|
| 346 |
| 00:29:59,260 --> 00:30:02,360 |
| the value in the middle. How many values do we have? |
|
|
| 347 |
| 00:30:02,800 --> 00:30:08,920 |
| There are nine values. So the middle is number |
|
|
| 348 |
| 00:30:08,920 --> 00:30:15,390 |
| five. One, two, three, four, five. So 16. This |
|
|
| 349 |
| 00:30:15,390 --> 00:30:23,010 |
| value is the median. Now look at the values below |
|
|
| 350 |
| 00:30:23,010 --> 00:30:29,650 |
| the median. There are four below and four above the |
|
|
| 351 |
| 00:30:29,650 --> 00:30:34,970 |
| median. Now let's see how can we compute Q1. The |
|
|
| 352 |
| 00:30:34,970 --> 00:30:38,250 |
| position of Q1, as we mentioned, is N plus 1 |
|
|
| 353 |
| 00:30:38,250 --> 00:30:42,630 |
| divided by 4. So N is 9 plus 1 divided by 4 is 2 |
|
|
| 354 |
| 00:30:42,630 --> 00:30:50,330 |
| .5. 2.5 position, it means you have to take the |
|
|
| 355 |
| 00:30:50,330 --> 00:30:54,490 |
| average of the two corresponding values, 2 and 3. |
|
|
| 356 |
| 00:30:55,130 --> 00:31:01,010 |
| So 2 and 3, so 12 plus 13 divided by 2. That gives |
|
|
| 357 |
| 00:31:01,010 --> 00:31:08,390 |
| 12.5. So this is Q1. |
|
|
| 358 |
| 00:31:08,530 --> 00:31:18,210 |
| So Q1 is 12.5. Now what's about Q3? The Q3, the |
|
|
| 359 |
| 00:31:18,210 --> 00:31:27,810 |
| rank position, Q1 was 2.5. So Q3 should be three |
|
|
| 360 |
| 00:31:27,810 --> 00:31:32,410 |
| times that value, because it's three times A plus |
|
|
| 361 |
| 00:31:32,410 --> 00:31:36,090 |
| 1 over 4. That means the rank position is 7.5. |
|
|
| 362 |
| 00:31:36,590 --> 00:31:39,410 |
| That means you have to take the average of the 7 |
|
|
| 363 |
| 00:31:39,410 --> 00:31:44,890 |
| and 8 position. 7 and 8 is 18, |
|
|
| 364 |
| 00:31:45,880 --> 00:31:56,640 |
| which is 19.5. So that's Q3, 19.5. |
|
|
| 365 |
| 00:32:00,360 --> 00:32:09,160 |
| So this is Q3. This value is Q1. And this value |
|
|
| 366 |
| 00:32:09,160 --> 00:32:15,910 |
| is? Now, Q2 is the center. It's located in the |
|
|
| 367 |
| 00:32:15,910 --> 00:32:18,570 |
| center because, as we mentioned, four below and |
|
|
| 368 |
| 00:32:18,570 --> 00:32:22,950 |
| four above. Now what's about Q1? Q1 is not in the |
|
|
| 369 |
| 00:32:22,950 --> 00:32:28,150 |
| center of the entire data. Because Q1, 12.5, so |
|
|
| 370 |
| 00:32:28,150 --> 00:32:31,830 |
| two points below and the others maybe how many |
|
|
| 371 |
| 00:32:31,830 --> 00:32:34,750 |
| above, two, four, six, seven observations above it. |
|
|
| 372 |
| 00:32:35,390 --> 00:32:40,130 |
| So that means Q1 is not the center. Also, Q3 is not |
|
|
| 373 |
| 00:32:40,130 --> 00:32:43,170 |
| the center because two observations above it and seven |
|
|
| 374 |
| 00:32:43,170 --> 00:32:48,780 |
| below it. So that means Q1 and Q3 are measures of |
|
|
| 375 |
| 00:32:48,780 --> 00:32:52,480 |
| non-central location, while the median is a |
|
|
| 376 |
| 00:32:52,480 --> 00:32:56,080 |
| measure of central location. But if you just look |
|
|
| 377 |
| 00:32:56,080 --> 00:33:03,720 |
| at the data below the median, just focus on the |
|
|
| 378 |
| 00:33:03,720 --> 00:33:09,100 |
| data below the median, 12.5 lies exactly in the |
|
|
| 379 |
| 00:33:09,100 --> 00:33:13,130 |
| middle of the data. So 12.5 is the center of the |
|
|
| 380 |
| 00:33:13,130 --> 00:33:18,090 |
| data. I mean, Q1 is the center of the data below |
|
|
| 381 |
| 00:33:18,090 --> 00:33:22,810 |
| the overall median. The overall median was 16. So |
|
|
| 382 |
| 00:33:22,810 --> 00:33:27,490 |
| the data before 16, the median for this data is 12 |
|
|
| 383 |
| 00:33:27,490 --> 00:33:31,770 |
| .5, which is the first part. Similarly, if you |
|
|
| 384 |
| 00:33:31,770 --> 00:33:36,870 |
| look at the data above Q2, |
|
|
| 385 |
| 00:33:37,770 --> 00:33:42,190 |
| now 19.5 is located in the middle of the line. So |
|
|
| 386 |
| 00:33:42,190 --> 00:33:46,470 |
| Q3 is a measure of the center for the data above the |
|
|
| 387 |
| 00:33:46,470 --> 00:33:48,390 |
| line. Make sense? |
|
|
| 388 |
| 00:33:51,370 --> 00:33:56,430 |
| So that's how we can compute the first, second, and |
|
|
| 389 |
| 00:33:56,430 --> 00:34:03,510 |
| third part. Any questions? Yes, but it's a whole |
|
|
| 390 |
| 00:34:03,510 --> 00:34:09,370 |
| number. Whole number, it means any integer. For |
|
|
| 391 |
| 00:34:09,370 --> 00:34:14,450 |
| example, yeah, exactly, yes. Suppose we have |
|
|
| 392 |
| 00:34:14,450 --> 00:34:18,090 |
| a number of data that is seven. |
|
|
| 393 |
| 00:34:22,070 --> 00:34:25,070 |
| The number of observations we have is seven. So the |
|
|
| 394 |
| 00:34:25,070 --> 00:34:29,730 |
| rank position, n plus one divided by two, seven |
|
|
| 395 |
| 00:34:29,730 --> 00:34:33,890 |
| plus one over two is four. Four means a whole |
|
|
| 396 |
| 00:34:33,890 --> 00:34:37,780 |
| number, I mean an integer. Then, in this case, just use |
|
|
| 397 |
| 00:34:37,780 --> 00:34:45,280 |
| it as it is. Now let's see the benefit or the |
|
|
| 398 |
| 00:34:45,280 --> 00:34:48,680 |
| feature of using Q1 and Q3. |
|
|
| 399 |
| 00:34:55,180 --> 00:35:01,300 |
| So let's move on to the inter-quartile range or |
|
|
| 400 |
| 00:35:01,300 --> 00:35:01,760 |
| IQR. |
|
|
| 401 |
| 00:35:08,020 --> 00:35:14,580 |
| 2.5 is the position. So the rank data of the ranked |
|
|
| 402 |
| 00:35:14,580 --> 00:35:19,180 |
| data. So take the average of the two corresponding |
|
|
| 403 |
| 00:35:19,180 --> 00:35:25,700 |
| values of this one, which are 2 and 3. So 2 and 3. |
|
|
| 404 |
| 00:35:27,400 --> |
|
|
| 445 |
| 00:39:11,650 --> 00:39:17,940 |
| because it covers the middle 50% of the data. IQR |
|
|
| 446 |
| 00:39:17,940 --> 00:39:20,120 |
| again is a measure of variability that is not |
|
|
| 447 |
| 00:39:20,120 --> 00:39:23,900 |
| influenced or affected by outliers or extreme |
|
|
| 448 |
| 00:39:23,900 --> 00:39:26,680 |
| values. So in the presence of outliers, it's |
|
|
| 449 |
| 00:39:26,680 --> 00:39:34,160 |
| better to use IQR instead of using the range. So |
|
|
| 450 |
| 00:39:34,160 --> 00:39:39,140 |
| again, median and the range are not affected by |
|
|
| 451 |
| 00:39:39,140 --> 00:39:43,180 |
| outliers. So in case of the presence of outliers, |
|
|
| 452 |
| 00:39:43,340 --> 00:39:46,380 |
| we have to use these measures, one as measure of |
|
|
| 453 |
| 00:39:46,380 --> 00:39:49,780 |
| central and the other as measure of spread. So |
|
|
| 454 |
| 00:39:49,780 --> 00:39:54,420 |
| measures like Q1, Q3, and IQR that are not |
|
|
| 455 |
| 00:39:54,420 --> 00:39:57,400 |
| influenced by outliers are called resistant |
|
|
| 456 |
| 00:39:57,400 --> 00:40:01,980 |
| measures. Resistance means in case of outliers, |
|
|
| 457 |
| 00:40:02,380 --> 00:40:06,120 |
| they remain in the same position or approximately |
|
|
| 458 |
| 00:40:06,120 --> 00:40:09,870 |
| in the same position. Because outliers don't |
|
|
| 459 |
| 00:40:09,870 --> 00:40:13,870 |
| affect these measures. I mean, don't affect Q1, |
|
|
| 460 |
| 00:40:14,830 --> 00:40:20,130 |
| Q3, and consequently IQR, because IQR is just the |
|
|
| 461 |
| 00:40:20,130 --> 00:40:24,990 |
| distance between Q3 and Q1. So to determine the |
|
|
| 462 |
| 00:40:24,990 --> 00:40:29,430 |
| value of IQR, you have first to compute Q1, Q3, |
|
|
| 463 |
| 00:40:29,750 --> 00:40:35,780 |
| then take the difference between these two. So, |
|
|
| 464 |
| 00:40:36,120 --> 00:40:41,120 |
| for example, suppose we have a data, and that data |
|
|
| 465 |
| 00:40:41,120 --> 00:40:51,400 |
| has Q1 equals 30, and Q3 is 55. Suppose for a data |
|
|
| 466 |
| 00:40:51,400 --> 00:41:00,140 |
| set, that data set has Q1 30, Q3 is 57. The IQR, |
|
|
| 467 |
| 00:41:00,800 --> 00:41:07,240 |
| or Inter Equal Hyper Range, 57 minus 30 is 27. Now |
|
|
| 468 |
| 00:41:07,240 --> 00:41:12,460 |
| what's the range? The range is maximum for the |
|
|
| 469 |
| 00:41:12,460 --> 00:41:17,380 |
| largest value, which is 17 minus 12. That gives |
|
|
| 470 |
| 00:41:17,380 --> 00:41:21,420 |
| 58. Now look at the difference between the two |
|
|
| 471 |
| 00:41:21,420 --> 00:41:26,900 |
| ranges. The inter-quartile range is 27. The range |
|
|
| 472 |
| 00:41:26,900 --> 00:41:29,800 |
| is 58. There is a big difference between these two |
|
|
| 473 |
| 00:41:29,800 --> 00:41:35,750 |
| values because range depends only on smallest and |
|
|
| 474 |
| 00:41:35,750 --> 00:41:40,190 |
| largest. And these values could be outliers. For |
|
|
| 475 |
| 00:41:40,190 --> 00:41:44,410 |
| this reason, the range value is higher or greater |
|
|
| 476 |
| 00:41:44,410 --> 00:41:48,410 |
| than the required range, which is just the |
|
|
| 477 |
| 00:41:48,410 --> 00:41:54,050 |
| distance of the 50% of the middle data. For this |
|
|
| 478 |
| 00:41:54,050 --> 00:41:59,470 |
| reason, it's better to use the range in case of |
|
|
| 479 |
| 00:41:59,470 --> 00:42:03,940 |
| outliers. Make sense? Any question? |
|
|
| 480 |
| 00:42:08,680 --> 00:42:19,320 |
| Five-number summary are smallest |
|
|
| 481 |
| 00:42:19,320 --> 00:42:27,380 |
| value, largest value, also first quartile, third |
|
|
| 482 |
| 00:42:27,380 --> 00:42:32,250 |
| quartile, and the median. These five numbers are |
|
|
| 483 |
| 00:42:32,250 --> 00:42:35,870 |
| called five-number summary, because by using these |
|
|
| 484 |
| 00:42:35,870 --> 00:42:41,590 |
| statistics, smallest, first, median, third |
|
|
| 485 |
| 00:42:41,590 --> 00:42:46,010 |
| quarter, and largest, you can describe the center |
|
|
| 486 |
| 00:42:46,010 --> 00:42:52,590 |
| spread and the shape of the distribution. So by |
|
|
| 487 |
| 00:42:52,590 --> 00:42:56,450 |
| using five-number summary, you can tell something |
|
|
| 488 |
| 00:42:56,450 --> 00:43:00,090 |
| about it. The center of the data, I mean the value |
|
|
| 489 |
| 00:43:00,090 --> 00:43:02,070 |
| in the middle, because the median is the value in |
|
|
| 490 |
| 00:43:02,070 --> 00:43:06,550 |
| the middle. Spread, because we can talk about the |
|
|
| 491 |
| 00:43:06,550 --> 00:43:11,070 |
| IQR, which is the range, and also the shape of the |
|
|
| 492 |
| 00:43:11,070 --> 00:43:15,450 |
| data. And let's see, let's move to this slide, |
|
|
| 493 |
| 00:43:16,670 --> 00:43:18,530 |
| slide number 50. |
|
|
| 494 |
| 00:43:21,530 --> 00:43:25,090 |
| Let's see how can we construct something called |
|
|
| 495 |
| 00:43:25,090 --> 00:43:31,850 |
| box plot. Box plot. Box plot can be constructed by |
|
|
| 496 |
| 00:43:31,850 --> 00:43:34,990 |
| using the five number summary. We have smallest |
|
|
| 497 |
| 00:43:34,990 --> 00:43:37,550 |
| value. On the other hand, we have the largest |
|
|
| 498 |
| 00:43:37,550 --> 00:43:43,430 |
| value. Also, we have Q1, the first quartile, the |
|
|
| 499 |
| 00:43:43,430 --> 00:43:47,510 |
| median, and Q3. For symmetric distribution, I mean |
|
|
| 500 |
| 00:43:47,510 --> 00:43:52,490 |
| if the data is bell-shaped. In this case, the |
|
|
| 501 |
| 00:43:52,490 --> 00:43:56,570 |
| vertical line in the box which represents the |
|
|
| 502 |
| 00:43:56,570 --> 00:43:59,730 |
| median should be located in the middle of this |
|
|
| 503 |
| 00:43:59,730 --> 00:44:05,510 |
| box, also in the middle of the entire data. Look |
|
|
| 504 |
| 00:44:05,510 --> 00:44:11,350 |
| carefully at this vertical line. This line splits |
|
|
| 505 |
| 00:44:11,350 --> 00:44:16,070 |
| the data into two halves, 25% to the left and 25% |
|
|
| 506 |
| 00:44:16,070 --> 00:44:19,960 |
| to the right. And also this vertical line splits |
|
|
| 507 |
| 00:44:19,960 --> 00:44:24,720 |
| the data into two halves, from the smallest to |
|
|
| 508 |
| 00:44:24,720 --> 00:44:29,760 |
| largest, because there are 50% of the observations |
|
|
| 509 |
| 00:44:29,760 --> 00:44:34,560 |
| lie below, and 50% lies above. So that means by |
|
|
| 510 |
| 00:44:34,560 --> 00:44:37,840 |
| using box plot, you can tell something about the |
|
|
| 511 |
| 00:44:37,840 --> 00:44:42,520 |
| shape of the distribution. So again, if the data |
|
|
| 512 |
| 00:44:42,520 --> 00:44:48,270 |
| are symmetric around the median, And the central |
|
|
| 513 |
| 00:44:48,270 --> 00:44:53,910 |
| line, this box, and central line are centered |
|
|
| 514 |
| 00:44:53,910 --> 00:44:57,550 |
| between the endpoints. I mean, this vertical line |
|
|
| 515 |
| 00:44:57,550 --> 00:45:00,720 |
| is centered between these two endpoints. between |
|
|
| 516 |
| 00:45:00,720 --> 00:45:04,180 |
| Q1 and Q3. And the whole box plot is centered |
|
|
| 517 |
| 00:45:04,180 --> 00:45:07,100 |
| between the smallest and the largest value. And |
|
|
| 518 |
| 00:45:07,100 --> 00:45:10,840 |
| also the distance between the median and the |
|
|
| 519 |
| 00:45:10,840 --> 00:45:14,320 |
| smallest is roughly equal to the distance between |
|
|
| 520 |
| 00:45:14,320 --> 00:45:19,760 |
| the median and the largest. So you can tell |
|
|
| 521 |
| 00:45:19,760 --> 00:45:22,660 |
| something about the shape of the distribution by |
|
|
| 522 |
| 00:45:22,660 --> 00:45:26,780 |
| using the box plot. |
|
|
| 523 |
| 00:45:32,870 --> 00:45:36,110 |
| The graph in the middle. Here median and median |
|
|
| 524 |
| 00:45:36,110 --> 00:45:40,110 |
| are the same. The box plot, we have here the |
|
|
| 525 |
| 00:45:40,110 --> 00:45:43,830 |
| median in the middle of the box, also in the |
|
|
| 526 |
| 00:45:43,830 --> 00:45:47,390 |
| middle of the entire data. So you can say that the |
|
|
| 527 |
| 00:45:47,390 --> 00:45:50,210 |
| distribution of this data is symmetric or is bell |
|
|
| 528 |
| 00:45:50,210 --> 00:45:55,750 |
| -shaped. It's normal distribution. On the other |
|
|
| 529 |
| 00:45:55,750 --> 00:46:00,110 |
| hand, if you look here, you will see that the |
|
|
| 530 |
| 00:46:00,110 --> 00:46:06,160 |
| median is not in the center of the box. It's near |
|
|
| 531 |
| 00:46:06,160 --> 00:46:12,580 |
| Q3. So the left tail, I mean, the distance between |
|
|
| 532 |
| 00:46:12,580 --> 00:46:16,620 |
| the median and the smallest, this tail is longer |
|
|
| 533 |
| 00:46:16,620 --> 00:46:20,600 |
| than the right tail. In this case, it's called |
|
|
| 534 |
| 00:46:20,600 --> 00:46:24,850 |
| left skewed or skewed to the left. or negative |
|
|
| 535 |
| 00:46:24,850 --> 00:46:29,510 |
| skewness. So if the data is not symmetric, it |
|
|
| 536 |
| 00:46:29,510 --> 00:46:35,630 |
| might be left skewed. I mean, the left tail is |
|
|
| 537 |
| 00:46:35,630 --> 00:46:40,590 |
| longer than the right tail. On the other hand, if |
|
|
| 538 |
| 00:46:40,590 --> 00:46:45,950 |
| the median is located near Q1, it means the right |
|
|
| 539 |
| 00:46:45,950 --> 00:46:49,930 |
| tail is longer than the left tail, and it's called |
|
|
| 540 |
| 00:46:49,930 --> 00:46:56,470 |
| positive skewed or right skewed. So for symmetric |
|
|
| 541 |
| 00:46:56,470 --> 00:47:00,310 |
| distribution, the median in the middle, for left |
|
|
| 542 |
| 00:47:00,310 --> 00:47:04,570 |
| or right skewed, the median either is close to the |
|
|
| 543 |
| 00:47:04,570 --> 00:47:09,930 |
| Q3 or skewed distribution to the left, or the |
|
|
| 544 |
| 00:47:09,930 --> 00:47:14,910 |
| median is close to Q1 and the distribution is |
|
|
| 545 |
| 00:47:14,910 --> 00:47:20,570 |
| right skewed or has positive skewness. That's how |
|
|
| 546 |
| 00:47:20,570 --> 00:47:25,860 |
| can we tell spread center and the shape by using |
|
|
| 547 |
| 00:47:25,860 --> 00:47:28,460 |
| the box plot. So center is the value in the |
|
|
| 548 |
| 00:47:28,460 --> 00:47:32,860 |
| middle, Q2 or the median. Spread is the distance |
|
|
| 549 |
| 00:47:32,860 --> 00:47:38,340 |
| between Q1 and Q3. So Q3 minus Q1 gives IQR. And |
|
|
| 550 |
| 00:47:38,340 --> 00:47:41,880 |
| finally, you can tell something about the shape of |
|
|
| 551 |
| 00:47:41,880 --> 00:47:45,140 |
| the distribution by just looking at the scatter |
|
|
| 552 |
| 00:47:45,140 --> 00:47:46,440 |
| plot. |
|
|
| 553 |
| 00:47:49,700 --> 00:47:56,330 |
| Let's look at This example, and suppose we have |
|
|
| 554 |
| 00:47:56,330 --> 00:48:02,430 |
| small data set. And let's see how can we construct |
|
|
| 555 |
| 00:48:02,430 --> 00:48:05,750 |
| the MaxPlot. In order to construct MaxPlot, you |
|
|
| 556 |
| 00:48:05,750 --> 00:48:09,510 |
| have to compute minimum first or smallest value, |
|
|
| 557 |
| 00:48:09,810 --> 00:48:14,650 |
| largest value. Besides that, you have to compute |
|
|
| 558 |
| 00:48:14,650 --> 00:48:21,110 |
| first and third part time and also Q2. For this |
|
|
| 559 |
| 00:48:21,110 --> 00:48:27,570 |
| simple example, Q1 is 2, Q3 is 5, and the median |
|
|
| 560 |
| 00:48:27,570 --> 00:48:33,990 |
| is 3. Smallest is 0, largest is 17. Now, be |
|
|
| 561 |
| 00:48:33,990 --> 00:48:38,130 |
| careful here, 17 seems to be an outlier. But so |
|
|
| 562 |
| 00:48:38,130 --> 00:48:44,190 |
| far, we don't explain how can we decide if a data |
|
|
| 563 |
| 00:48:44,190 --> 00:48:47,550 |
| value is considered to be an outlier. But at least |
|
|
| 564 |
| 00:48:47,550 --> 00:48:53,080 |
| 17. is a suspected value to be an outlier, seems |
|
|
| 565 |
| 00:48:53,080 --> 00:48:57,200 |
| to be. Sometimes you are 95% sure that that point |
|
|
| 566 |
| 00:48:57,200 --> 00:49:00,160 |
| is an outlier, but you cannot tell, because you |
|
|
| 567 |
| 00:49:00,160 --> 00:49:04,060 |
| have to have a specific rule that can decide if |
|
|
| 568 |
| 00:49:04,060 --> 00:49:07,400 |
| that point is an outlier or not. But at least it |
|
|
| 569 |
| 00:49:07,400 --> 00:49:12,060 |
| makes sense that that point is considered maybe an |
|
|
| 570 |
| 00:49:12,060 --> 00:49:14,700 |
| outlier. But let's see how can we construct that |
|
|
| 571 |
| 00:49:14,700 --> 00:49:18,190 |
| first. The box plot. Again, as we mentioned, the |
|
|
| 572 |
| 00:49:18,190 --> 00:49:21,630 |
| minimum value is zero. The maximum is 27. The Q1 |
|
|
| 573 |
| 00:49:21,630 --> 00:49:27,830 |
| is 2. The median is 3. The Q3 is 5. Now, if you |
|
|
| 574 |
| 00:49:27,830 --> 00:49:32,010 |
| look at the distance between, does this vertical |
|
|
| 575 |
| 00:49:32,010 --> 00:49:35,790 |
| line lie between the line in the middle or the |
|
|
| 576 |
| 00:49:35,790 --> 00:49:40,090 |
| center of the box? It's not exactly. But if you |
|
|
| 577 |
| 00:49:40,090 --> 00:49:45,260 |
| look at this line, vertical line, and the location |
|
|
| 578 |
| 00:49:45,260 --> 00:49:50,600 |
| of this with respect to the minimum and the |
|
|
| 579 |
| 00:49:50,600 --> 00:49:56,640 |
| maximum. You will see that the right tail is much |
|
|
| 580 |
| 00:49:56,640 --> 00:50:01,560 |
| longer than the left tail because it starts from 3 |
|
|
| 581 |
| 00:50:01,560 --> 00:50:06,180 |
| up to 27. And the other one, from zero to three, |
|
|
| 582 |
| 00:50:06,380 --> 00:50:09,760 |
| is a big distance between three and 27, compared |
|
|
| 583 |
| 00:50:09,760 --> 00:50:13,140 |
| to the other one, zero to three. So it seems to be |
|
|
| 584 |
| 00:50:13,140 --> 00:50:16,600 |
| this is quite skewed, so it's not at all |
|
|
| 585 |
| 00:50:16,600 --> 00:50:23,700 |
| symmetric, because of this value. So maybe by |
|
|
| 586 |
| 00:50:23,700 --> 00:50:25,580 |
| using MaxPlot, you can tell that point is |
|
|
| 587 |
| 00:50:25,580 --> 00:50:31,440 |
| suspected to be an outlier. It has a very long |
|
|
| 588 |
| 00:50:31,440 --> 00:50:32,800 |
| right tail. |
|
|
| 589 |
| 00:50:35,560 --> 00:50:41,120 |
| So let's see how can we determine if a point is an |
|
|
| 590 |
| 00:50:41,120 --> 00:50:50,400 |
| outlier or not. Sometimes we can use box plot to |
|
|
| 591 |
| 00:50:50,400 --> 00:50:53,840 |
| determine if the point is an outlier or not. The |
|
|
| 592 |
| 00:50:53,840 --> 00:51:00,860 |
| rule is that a value is considered an outlier It |
|
|
| 593 |
| 00:51:00,860 --> 00:51:04,780 |
| is more than 1.5 times the entire quartile range |
|
|
| 594 |
| 00:51:04,780 --> 00:51:11,420 |
| below Q1 or above it. Let's explain the meaning of |
|
|
| 595 |
| 00:51:11,420 --> 00:51:12,260 |
| this sentence. |
|
|
| 596 |
| 00:51:15,260 --> 00:51:20,100 |
| First, let's compute something called lower. |
|
|
| 597 |
| 00:51:23,740 --> 00:51:28,540 |
| The lower limit is |
|
|
| 598 |
| 00:51:28,540 --> 00:51:38,680 |
| not the minimum. It's Q1 minus 1.5 IQR. This is |
|
|
| 599 |
| 00:51:38,680 --> 00:51:39,280 |
| the lower limit. |
|
|
| 600 |
| 00:51:42,280 --> 00:51:47,560 |
| So it's 1.5 times IQR below Q1. This is the lower |
|
|
| 601 |
| 00:51:47,560 --> 00:51:50,620 |
| limit. The upper limit, |
|
|
| 602 |
| 00:51:54,680 --> 00:51:57,460 |
| Q3, |
|
|
| 603 |
| 00:51:58,790 --> 00:52:06,890 |
| plus 1.5 times IQR. So we computed lower and upper |
|
|
| 604 |
| 00:52:06,890 --> 00:52:13,350 |
| limit by using these rules. Q1 minus 1.5 IQR. So |
|
|
| 605 |
| 00:52:13,350 --> 00:52:20,510 |
| it's 1.5 times IQR below Q1 and 1.5 times IQR |
|
|
| 606 |
| 00:52:20,510 --> 00:52:25,070 |
| above Q1. Now, any value. |
|
|
| 607 |
| 00:52:31,150 --> 00:52:38,610 |
| Is it smaller than the |
|
|
| 608 |
| 00:52:38,610 --> 00:52:45,990 |
| lower limit or |
|
|
| 609 |
| 00:52:45,990 --> 00:52:53,290 |
| greater than the |
|
|
| 610 |
| 00:52:53,290 --> 00:52:54,150 |
| upper limit? |
|
|
| 611 |
| 00:52:58,330 --> 00:53:04,600 |
| Any value. smaller than the lower limit and |
|
|
| 612 |
| 00:53:04,600 --> 00:53:13,260 |
| greater than the upper limit is considered to |
|
|
| 613 |
| 00:53:13,260 --> 00:53:20,720 |
| be an outlier. This is the rule how can you tell |
|
|
| 614 |
| 00:53:20,720 --> 00:53:24,780 |
| if the point or data value is outlier or not. Just |
|
|
| 615 |
| 00:53:24,780 --> 00:53:27,100 |
| compute lower limit and upper limit. |
|
|
| 616 |
| 00:53:29,780 --> 00:53:35,580 |
| So lower limit, Q1 minus 1.5IQ3. Upper limit, Q3 |
|
|
| 617 |
| 00:53:35,580 --> 00:53:38,620 |
| plus 1.5. This is a constant. |
|
|
| 618 |
| 00:53:43,200 --> 00:53:47,040 |
| Now let's go back to the previous example, which |
|
|
| 619 |
| 00:53:47,040 --> 00:53:53,800 |
| was, which Q1 was, what's the value of Q1? Q1 was |
|
|
| 620 |
| 00:53:53,800 --> 00:53:57,680 |
| 2. Q3 is 5. |
|
|
| 621 |
| 00:54:00,650 --> 00:54:05,230 |
| In order to turn an outlier, you don't need the |
|
|
| 622 |
| 00:54:05,230 --> 00:54:11,150 |
| value, the median. Now, Q3 is 5, Q1 is 2, so IQR |
|
|
| 623 |
| 00:54:11,150 --> 00:54:21,050 |
| is 3. That's the value of IQR. Now, lower limit, A |
|
|
| 624 |
| 00:54:21,050 --> 00:54:31,830 |
| times 2 minus 1.5 times IQR3. So that's minus 2.5. |
|
|
| 625 |
| 00:54:33,550 --> 00:54:41,170 |
| U3 plus U3 is 3. It's 5, sorry. It's 5 plus 1.5. |
|
|
| 626 |
| 00:54:41,650 --> 00:54:48,570 |
| That gives 9.5. Now, any point or any data value, |
|
|
| 627 |
| 00:54:49,450 --> 00:54:55,950 |
| any data value falls below minus 2.5. I mean |
|
|
| 628 |
| 00:54:55,950 --> 00:55:00,380 |
| smaller than minus 2. |