| 1 |
| 00:00:06,480 --> 00:00:12,100 |
| Last time, I mean Tuesday, we discussed box plot |
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| 2 |
| 00:00:12,100 --> 00:00:19,540 |
| and we introduced how can we use box plot to |
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| 3 |
| 00:00:19,540 --> 00:00:24,160 |
| determine if any point is suspected to be an |
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| 4 |
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| outlier by using the lower limit and upper limit. |
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| 5 |
| 00:00:29,460 --> 00:00:32,980 |
| And we mentioned last time that if any point is |
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| 6 |
| 00:00:32,980 --> 00:00:38,580 |
| below the lower limit or is above the upper limit, |
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| 7 |
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| that point is considered to be an outlier. So |
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| 8 |
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| that's one of the usage of the backsplat. I mean, |
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| 9 |
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| for this specific example, we mentioned last time |
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| 10 |
| 00:00:51,360 --> 00:00:56,910 |
| 27 is an outlier. And also here you can tell also |
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| 11 |
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| the data are right skewed because the right tail |
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| 12 |
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| exactly is much longer than the left tail. I mean |
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| 13 |
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| the distance between or from the median and the |
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| 14 |
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| maximum value is bigger or larger than the |
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| 15 |
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| distance from the median to the smallest value. |
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| 16 |
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| That means the data is not symmetric, it's quite |
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| 17 |
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| skewed to the right. In this case, you cannot use |
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| 18 |
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| the mean or the range as a measure of spread and |
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| 19 |
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| median and, I'm sorry, mean as a measure of |
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| 20 |
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| tendency. Because these measures are affected by |
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| 21 |
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| outcomes. In this case, you have to use the median |
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| 22 |
| 00:01:39,450 --> 00:01:43,690 |
| instead of the mean and IQR instead of the range |
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| 23 |
| 00:01:43,690 --> 00:01:48,090 |
| because IQR is the mid-spread of the data because |
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| 24 |
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| we just take the range from Q3 to Q1. That means |
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| 25 |
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| we ignore The data below Q1 and data after Q3. |
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| 26 |
| 00:01:57,970 --> 00:02:01,370 |
| That means IQR is not affected by outlier and it's |
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| 27 |
| 00:02:01,370 --> 00:02:04,610 |
| better to use it instead of R, of the range. |
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| 28 |
| 00:02:07,470 --> 00:02:10,950 |
| If the data has an outlier, it's better just to |
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| 29 |
| 00:02:10,950 --> 00:02:13,990 |
| make a star or circle for the box plot because |
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| 30 |
| 00:02:13,990 --> 00:02:17,250 |
| this one mentioned that that point is an outlier. |
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| 31 |
| 00:02:18,390 --> 00:02:21,390 |
| Sometimes outlier is maximum value or the largest |
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| 32 |
| 00:02:21,390 --> 00:02:25,000 |
| value you have. sometimes maybe the minimum value. |
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| 33 |
| 00:02:25,520 --> 00:02:28,480 |
| So it depends on the data. For this example, 27, |
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| 34 |
| 00:02:28,720 --> 00:02:33,360 |
| which was the maximum, is an outlier. But zero is |
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| 35 |
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| not outlier in this case, because zero is above |
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| 36 |
| 00:02:36,520 --> 00:02:41,500 |
| the lower limit. Let's move to the next topic, |
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| 37 |
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| which talks about covariance and correlation. |
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| 38 |
| 00:02:48,960 --> 00:02:51,740 |
| Later, we'll talk in more details about |
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| 39 |
| 00:02:53,020 --> 00:02:56,060 |
| Correlation and regression, that's when maybe |
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| 40 |
| 00:02:56,060 --> 00:03:02,840 |
| chapter 11 or 12. But here we just show how can we |
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| 41 |
| 00:03:02,840 --> 00:03:05,420 |
| compute the covariance of the correlation |
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| 42 |
| 00:03:05,420 --> 00:03:10,220 |
| coefficient and what's the meaning of that value |
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| 43 |
| 00:03:10,220 --> 00:03:15,840 |
| we have. The covariance means it measures the |
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| 44 |
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| strength of the linear relationship between two |
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| 45 |
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| numerical variables. That means if the data set is |
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| 46 |
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| numeric, I mean if both variables are numeric, in |
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| 47 |
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| this case we can use the covariance to measure the |
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| 48 |
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| strength of the linear association or relationship |
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| 49 |
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| between two numerical variables. Now the formula |
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| 50 |
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| is used to compute the covariance given by this |
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| 51 |
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| one. It's summation of the product of xi minus x |
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| 52 |
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| bar, yi minus y bar, divided by n minus 1. |
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| 53 |
| 00:03:59,660 --> 00:04:03,120 |
| So we need first to compute the means of x and y, |
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| 54 |
| 00:04:03,620 --> 00:04:07,680 |
| then find x minus x bar times y minus y bar, then |
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| 55 |
| 00:04:07,680 --> 00:04:11,160 |
| sum all of these values, then divide by n minus 1. |
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| 56 |
| 00:04:12,870 --> 00:04:17,770 |
| The covariance only concerned with the strength of |
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| 57 |
| 00:04:17,770 --> 00:04:23,370 |
| the relationship. By using the sign of the |
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| 58 |
| 00:04:23,370 --> 00:04:27,010 |
| covariance, you can tell if there exists positive |
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| 59 |
| 00:04:27,010 --> 00:04:31,070 |
| or negative relationship between the two |
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| 60 |
| 00:04:31,070 --> 00:04:33,710 |
| variables. For example, if the covariance between |
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| 61 |
| 00:04:33,710 --> 00:04:42,760 |
| x and y is positive, that means x and y move In |
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| 62 |
| 00:04:42,760 --> 00:04:48,080 |
| the same direction. It means that if X goes up, Y |
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| 63 |
| 00:04:48,080 --> 00:04:52,260 |
| will go in the same position. If X goes down, also |
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| 64 |
| 00:04:52,260 --> 00:04:55,660 |
| Y goes down. For example, suppose we are |
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| 65 |
| 00:04:55,660 --> 00:04:57,920 |
| interested in the relationship between consumption |
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| 66 |
| 00:04:57,920 --> 00:05:02,440 |
| and income. We know that if income increases, if |
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| 67 |
| 00:05:02,440 --> 00:05:07,160 |
| income goes up, if your salary goes up, that means |
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| 68 |
| 00:05:07,160 --> 00:05:13,510 |
| consumption also will go up. So that means they go |
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| 69 |
| 00:05:13,510 --> 00:05:18,650 |
| in the same or move in the same position. So for |
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| 70 |
| 00:05:18,650 --> 00:05:20,690 |
| sure, the covariance between X and Y should be |
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| 71 |
| 00:05:20,690 --> 00:05:25,550 |
| positive. On the other hand, if the covariance |
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| 72 |
| 00:05:25,550 --> 00:05:31,110 |
| between X and Y is negative, that means X goes up. |
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| 73 |
| 00:05:32,930 --> 00:05:36,370 |
| Y will go to the same, to the opposite direction. |
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| 74 |
| 00:05:36,590 --> 00:05:40,090 |
| I mean they move to opposite direction. That means |
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| 75 |
| 00:05:40,090 --> 00:05:42,230 |
| there exists negative relationship between X and |
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| 76 |
| 00:05:42,230 --> 00:05:47,630 |
| Y. For example, you score in statistics a number |
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| 77 |
| 00:05:47,630 --> 00:05:55,220 |
| of missing classes. If you miss more classes, it |
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| 78 |
| 00:05:55,220 --> 00:05:59,860 |
| means your score will go down so as x increases y |
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| 79 |
| 00:05:59,860 --> 00:06:04,820 |
| will go down so there is positive relationship or |
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| 80 |
| 00:06:04,820 --> 00:06:08,720 |
| negative relationship between x and y i mean x |
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| 81 |
| 00:06:08,720 --> 00:06:12,020 |
| goes up the other go in the same direction |
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| 82 |
| 00:06:12,020 --> 00:06:16,500 |
| sometimes |
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| 83 |
| 00:06:16,500 --> 00:06:21,800 |
| there is exist no relationship between x and y In |
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| 84 |
| 00:06:21,800 --> 00:06:24,780 |
| that case, covariance between x and y equals zero. |
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| 85 |
| 00:06:24,880 --> 00:06:31,320 |
| For example, your score in statistics and your |
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| 86 |
| 00:06:31,320 --> 00:06:31,700 |
| weight. |
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| 87 |
| 00:06:34,540 --> 00:06:36,760 |
| It makes sense that there is no relationship |
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| 88 |
| 00:06:36,760 --> 00:06:42,680 |
| between your weight and your score. In this case, |
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| 89 |
| 00:06:43,580 --> 00:06:46,760 |
| we are saying x and y are independent. I mean, |
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| 90 |
| 00:06:46,840 --> 00:06:50,790 |
| they are uncorrelated. Because as one variable |
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| 91 |
| 00:06:50,790 --> 00:06:56,010 |
| increases, the other maybe go up or go down. Or |
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| 92 |
| 00:06:56,010 --> 00:06:59,690 |
| maybe constant. So that means there exists no |
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| 93 |
| 00:06:59,690 --> 00:07:02,390 |
| relationship between the two variables. In that |
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| 94 |
| 00:07:02,390 --> 00:07:05,950 |
| case, the covariance between x and y equals zero. |
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| 95 |
| 00:07:06,450 --> 00:07:09,210 |
| Now, by using the covariance, you can determine |
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| 96 |
| 00:07:09,210 --> 00:07:12,710 |
| the direction of the relationship. I mean, you can |
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| 97 |
| 00:07:12,710 --> 00:07:14,850 |
| just figure out if the relation is positive or |
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| 98 |
| 00:07:14,850 --> 00:07:18,980 |
| negative. But you cannot tell exactly the strength |
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| 99 |
| 00:07:18,980 --> 00:07:22,100 |
| of the relationship. I mean you cannot tell if |
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| 100 |
| 00:07:22,100 --> 00:07:27,640 |
| they exist. strong moderate or weak relationship |
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| 101 |
| 00:07:27,640 --> 00:07:31,040 |
| just you can tell there exists positive or |
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| 102 |
| 00:07:31,040 --> 00:07:33,520 |
| negative or maybe the relationship does not exist |
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| 103 |
| 00:07:33,520 --> 00:07:36,580 |
| but you cannot tell the exact strength of the |
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| 104 |
| 00:07:36,580 --> 00:07:40,120 |
| relationship by using the value of the covariance |
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| 105 |
| 00:07:40,120 --> 00:07:43,060 |
| I mean the size of the covariance does not tell |
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| 106 |
| 00:07:43,060 --> 00:07:48,520 |
| anything about the strength so generally speaking |
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| 107 |
| 00:07:48,520 --> 00:07:53,150 |
| covariance between x and y measures the strength |
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| 108 |
| 00:07:53,150 --> 00:07:58,590 |
| of two numerical variables, and you only tell if |
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| 109 |
| 00:07:58,590 --> 00:08:01,270 |
| there exists positive or negative relationship, |
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| 110 |
| 00:08:01,770 --> 00:08:04,510 |
| but you cannot tell anything about the strength of |
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| 111 |
| 00:08:04,510 --> 00:08:06,910 |
| the relationship. Any questions? |
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| 112 |
| 00:08:09,610 --> 00:08:15,210 |
| So let me ask you just to summarize what I said so |
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| 113 |
| 00:08:15,210 --> 00:08:21,100 |
| far. Just give me the summary or conclusion. of |
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| 114 |
| 00:08:21,100 --> 00:08:24,670 |
| the covariance. The value of the covariance |
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| 115 |
| 00:08:24,670 --> 00:08:26,810 |
| determine if the relationship between the |
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| 116 |
| 00:08:26,810 --> 00:08:29,410 |
| variables are positive or negative or there is no |
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| 117 |
| 00:08:29,410 --> 00:08:31,970 |
| relationship that when the covariance is more than |
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| 118 |
| 00:08:31,970 --> 00:08:34,170 |
| zero, the meaning that it's positive, the |
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| 119 |
| 00:08:34,170 --> 00:08:36,930 |
| relationship is positive and one variable go up, |
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| 120 |
| 00:08:37,290 --> 00:08:39,590 |
| another go up and vice versa. And when the |
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| 121 |
| 00:08:39,590 --> 00:08:41,810 |
| covariance is less than zero, there is negative |
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| 122 |
| 00:08:41,810 --> 00:08:44,250 |
| relationship and the meaning that when one |
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| 123 |
| 00:08:44,250 --> 00:08:47,490 |
| variable go up, the other goes down and vice versa |
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| 124 |
| 00:08:47,490 --> 00:08:50,550 |
| and when the covariance equals zero, there is no |
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| 125 |
| 00:08:50,550 --> 00:08:53,350 |
| relationship between the variables. And what's |
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| 126 |
| 00:08:53,350 --> 00:08:54,930 |
| about the strength? |
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| 127 |
| 00:08:57,950 --> 00:09:03,450 |
| So just tell the direction, not the strength of |
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| 128 |
| 00:09:03,450 --> 00:09:08,610 |
| the relationship. Now, in order to determine both |
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| 129 |
| 00:09:08,610 --> 00:09:12,110 |
| the direction and the strength, we can use the |
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| 130 |
| 00:09:12,110 --> 00:09:17,580 |
| coefficient of correlation. The coefficient of |
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| 131 |
| 00:09:17,580 --> 00:09:20,320 |
| correlation measures the relative strength of the |
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| 132 |
| 00:09:20,320 --> 00:09:22,780 |
| linear relationship between two numerical |
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| 133 |
| 00:09:22,780 --> 00:09:27,940 |
| variables. The simplest formula that can be used |
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| 134 |
| 00:09:27,940 --> 00:09:31,220 |
| to compute the correlation coefficient is given by |
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| 135 |
| 00:09:31,220 --> 00:09:34,440 |
| this one. Maybe this is the easiest formula you |
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| 136 |
| 00:09:34,440 --> 00:09:38,060 |
| can use. I mean, it's shortcut formula for |
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| 137 |
| 00:09:38,060 --> 00:09:40,860 |
| computation. There are many other formulas to |
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| 138 |
| 00:09:40,860 --> 00:09:44,490 |
| compute the correlation. This one is the easiest |
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| 139 |
| 00:09:44,490 --> 00:09:52,570 |
| one. R is just sum of xy minus n, n is the sample |
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| 140 |
| 00:09:52,570 --> 00:09:57,570 |
| size, times x bar is the sample mean, y bar is the |
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| 141 |
| 00:09:57,570 --> 00:10:01,090 |
| sample mean for y, because here we have two |
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| 142 |
| 00:10:01,090 --> 00:10:06,250 |
| variables, divided by square root, don't forget |
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| 143 |
| 00:10:06,250 --> 00:10:11,490 |
| the square root, of two quantities. One conserved |
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| 144 |
| 00:10:11,490 --> 00:10:15,710 |
| for x and the other for y. The first one, sum of x |
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| 145 |
| 00:10:15,710 --> 00:10:18,850 |
| squared minus nx bar squared. The other one is |
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| 146 |
| 00:10:18,850 --> 00:10:21,830 |
| similar just for the other variables, sum y |
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| 147 |
| 00:10:21,830 --> 00:10:26,090 |
| squared minus ny bar squared. So in order to |
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| 148 |
| 00:10:26,090 --> 00:10:28,650 |
| determine the value of R, we need, |
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| 149 |
| 00:10:32,170 --> 00:10:35,890 |
| suppose for example, we have x and y, theta x and |
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| 150 |
| 00:10:35,890 --> 00:10:36,110 |
| y. |
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| 151 |
| 00:10:40,350 --> 00:10:44,730 |
| x is called explanatory |
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| 152 |
| 00:10:44,730 --> 00:10:54,390 |
| variable and |
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| 153 |
| 00:10:54,390 --> 00:11:04,590 |
| y is called response variable |
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| 154 |
| 00:11:04,590 --> 00:11:07,970 |
| sometimes x is called independent |
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| 155 |
| 00:11:21,760 --> 00:11:25,320 |
| For example, suppose we are talking about |
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| 156 |
| 00:11:25,320 --> 00:11:32,280 |
| consumption and |
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| 157 |
| 00:11:32,280 --> 00:11:36,700 |
| input. And we are interested in the relationship |
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| 158 |
| 00:11:36,700 --> 00:11:41,360 |
| between these two variables. Now, except for the |
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| 159 |
| 00:11:41,360 --> 00:11:44,900 |
| variable or the independent, this one affects the |
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| 160 |
| 00:11:44,900 --> 00:11:49,840 |
| other variable. As we mentioned, as your income |
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| 161 |
| 00:11:49,840 --> 00:11:53,800 |
| increases, your consumption will go in the same |
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| 162 |
| 00:11:53,800 --> 00:11:59,580 |
| direction, increases also. Income causes Y, or |
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| 163 |
| 00:11:59,580 --> 00:12:04,340 |
| income affects Y. In this case, income is your X. |
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| 164 |
| 00:12:06,180 --> 00:12:07,780 |
| Most of the time we use |
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| 165 |
| 00:12:10,790 --> 00:12:15,590 |
| And Y for independent. So in this case, the |
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| 166 |
| 00:12:15,590 --> 00:12:19,370 |
| response variable or your outcome or the dependent |
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| 167 |
| 00:12:19,370 --> 00:12:23,110 |
| variable is your consumption. So Y is consumption, |
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| 168 |
| 00:12:23,530 --> 00:12:29,150 |
| X is income. So now in order to determine the |
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| 169 |
| 00:12:29,150 --> 00:12:32,950 |
| correlation coefficient, we have the data of X and |
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| 170 |
| 00:12:32,950 --> 00:12:33,210 |
| Y. |
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| 171 |
| 00:12:36,350 --> 00:12:39,190 |
| The values of X, I mean the number of pairs of X |
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| 172 |
| 00:12:39,190 --> 00:12:41,990 |
| should be equal to the number of pairs of Y. So if |
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| 173 |
| 00:12:41,990 --> 00:12:44,930 |
| we have ten observations for X, we should have the |
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| 174 |
| 00:12:44,930 --> 00:12:50,010 |
| same number of observations for Y. It's pairs. X1, |
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| 175 |
| 00:12:50,090 --> 00:12:54,750 |
| Y1, X2, Y2, and so on. Now, the formula to compute |
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| 176 |
| 00:12:54,750 --> 00:13:04,170 |
| R, the shortcut formula is sum of XY minus N times |
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| 177 |
| 00:13:04,970 --> 00:13:09,630 |
| x bar, y bar, divided by the square root of two |
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| 178 |
| 00:13:09,630 --> 00:13:12,770 |
| quantities. The first one, sum of x squared minus |
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| 179 |
| 00:13:12,770 --> 00:13:17,270 |
| n x bar. The other one, sum of y squared minus ny |
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| 180 |
| 00:13:17,270 --> 00:13:21,710 |
| y squared. So the first thing we have to do is to |
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| 181 |
| 00:13:21,710 --> 00:13:24,210 |
| find the mean for each x and y. |
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| 182 |
| 00:13:28,230 --> 00:13:37,210 |
| So first step, compute x bar and y bar. Next, if |
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| 183 |
| 00:13:37,210 --> 00:13:41,690 |
| you look here, we have x and y, x times y. So we |
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| 184 |
| 00:13:41,690 --> 00:13:48,870 |
| need to compute the product of x times y. So just |
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| 185 |
| 00:13:48,870 --> 00:13:53,870 |
| for example, suppose x is 10, y is 5. So x times y |
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| 186 |
| 00:13:53,870 --> 00:13:54,970 |
| is 50. |
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| 187 |
| 00:13:57,810 --> 00:13:59,950 |
| In addition to that, you have to compute |
|
|
| 188 |
| 00:14:06,790 --> 00:14:12,470 |
| 100 x squared and y squared. It's like 125. |
|
|
| 189 |
| 00:14:14,810 --> 00:14:18,870 |
| Do the same calculations for the rest of the data |
|
|
| 190 |
| 00:14:18,870 --> 00:14:22,290 |
| you have. We have other data here, so we have to |
|
|
| 191 |
| 00:14:22,290 --> 00:14:25,410 |
| compute the same for the others. |
|
|
| 192 |
| 00:14:28,470 --> 00:14:33,250 |
| Then finally, just add xy, x squared, y squared. |
|
|
| 193 |
| 00:14:35,910 --> 00:14:40,830 |
| The values you have here in this formula, in order |
|
|
| 194 |
| 00:14:40,830 --> 00:14:44,830 |
| to compute the coefficient. |
|
|
| 195 |
| 00:14:54,250 --> 00:15:00,070 |
| Now, this value ranges between minus one and plus |
|
|
| 196 |
| 00:15:00,070 --> 00:15:00,370 |
| one. |
|
|
| 197 |
| 00:15:06,520 --> 00:15:10,800 |
| So it's between minus one and plus one. That means |
|
|
| 198 |
| 00:15:10,800 --> 00:15:15,840 |
| it's never smaller |
|
|
| 199 |
| 00:15:15,840 --> 00:15:20,200 |
| than minus one or greater than one. It's between |
|
|
| 200 |
| 00:15:20,200 --> 00:15:21,480 |
| minus one and plus one. |
|
|
| 201 |
| 00:15:24,360 --> 00:15:28,300 |
| Make sense? I mean if your value is suppose you |
|
|
| 202 |
| 00:15:28,300 --> 00:15:34,520 |
| did mistake for any of these computations and R |
|
|
| 203 |
| 00:15:34,520 --> 00:15:41,710 |
| might be 1.15, 115. That means there is an error. |
|
|
| 204 |
| 00:15:42,270 --> 00:15:45,870 |
| Or for example, if R is negative 1.5, that means |
|
|
| 205 |
| 00:15:45,870 --> 00:15:49,610 |
| there is a mistake. So you have to find or figure |
|
|
| 206 |
| 00:15:49,610 --> 00:15:55,670 |
| out what is that mistake. So that's simple |
|
|
| 207 |
| 00:15:55,670 --> 00:15:59,090 |
| calculations. Usually in the exam, we will give |
|
|
| 208 |
| 00:15:59,090 --> 00:16:01,350 |
| the formula for the correlation coefficient, as we |
|
|
| 209 |
| 00:16:01,350 --> 00:16:03,590 |
| mentioned before. In addition to that, we will |
|
|
| 210 |
| 00:16:03,590 --> 00:16:04,330 |
| give the summation. |
|
|
| 211 |
| 00:16:07,780 --> 00:16:12,720 |
| The sum of xy is given, sum x squared and sum y |
|
|
| 212 |
| 00:16:12,720 --> 00:16:18,320 |
| squared. Also sum of x and sum of y, in order to |
|
|
| 213 |
| 00:16:18,320 --> 00:16:22,320 |
| determine the means of x and y. For example, |
|
|
| 214 |
| 00:16:22,520 --> 00:16:26,860 |
| suppose I give sum of xi and i goes from 1 to 10 |
|
|
| 215 |
| 00:16:26,860 --> 00:16:31,760 |
| is 700, for example. You have to know that the |
|
|
| 216 |
| 00:16:31,760 --> 00:16:38,720 |
| sample size is 10, so x bar. is 700 divided by 10, |
|
|
| 217 |
| 00:16:39,320 --> 00:16:46,180 |
| so it's 7. Then use the curve to compute the |
|
|
| 218 |
| 00:16:46,180 --> 00:16:52,000 |
| coefficient of correlation. Questions? I think |
|
|
| 219 |
| 00:16:52,000 --> 00:16:55,900 |
| straightforward, maybe the easiest topic in this |
|
|
| 220 |
| 00:16:55,900 --> 00:17:02,980 |
| book is to compute the coefficient of correlation |
|
|
| 221 |
| 00:17:02,980 --> 00:17:09,070 |
| or correlation coefficient. Now my question is, do |
|
|
| 222 |
| 00:17:09,070 --> 00:17:13,090 |
| you think outliers affect the correlation |
|
|
| 223 |
| 00:17:13,090 --> 00:17:13,690 |
| coefficient? |
|
|
| 224 |
| 00:17:17,010 --> 00:17:23,210 |
| We said last time outliers affect the mean, the |
|
|
| 225 |
| 00:17:23,210 --> 00:17:28,310 |
| range, the variance. Now the question is, do |
|
|
| 226 |
| 00:17:28,310 --> 00:17:33,510 |
| outliers affect the correlation? |
|
|
| 227 |
| 00:17:37,410 --> 00:17:38,170 |
| Y. |
|
|
| 228 |
| 00:17:43,830 --> 00:17:51,330 |
| Exactly. The formula for R has X bar in it or Y |
|
|
| 229 |
| 00:17:51,330 --> 00:17:56,670 |
| bar. So it means outliers affect |
|
|
| 230 |
| 00:17:56,670 --> 00:18:01,210 |
| the correlation coefficient. So the answer is yes. |
|
|
| 231 |
| 00:18:03,470 --> 00:18:06,410 |
| Here we have x bar and y bar. Also, there is |
|
|
| 232 |
| 00:18:06,410 --> 00:18:10,690 |
| another formula to compute R. That formula is |
|
|
| 233 |
| 00:18:10,690 --> 00:18:13,370 |
| given by covariance between x and y. |
|
|
| 234 |
| 00:18:17,510 --> 00:18:21,930 |
| These two formulas are quite similar. I mean, by |
|
|
| 235 |
| 00:18:21,930 --> 00:18:26,070 |
| using this one, we can end with this formula. So |
|
|
| 236 |
| 00:18:26,070 --> 00:18:33,090 |
| this formula depends on this x is y. standard |
|
|
| 237 |
| 00:18:33,090 --> 00:18:36,170 |
| deviations of X and Y. That means outlier will |
|
|
| 238 |
| 00:18:36,170 --> 00:18:42,530 |
| affect the correlation coefficient. So in case of |
|
|
| 239 |
| 00:18:42,530 --> 00:18:45,670 |
| outliers, R could be changed. |
|
|
| 240 |
| 00:18:51,170 --> 00:18:55,530 |
| That formula is called simple correlation |
|
|
| 241 |
| 00:18:55,530 --> 00:18:58,790 |
| coefficient. On the other hand, we have population |
|
|
| 242 |
| 00:18:58,790 --> 00:19:02,200 |
| correlation coefficient. If you remember last |
|
|
| 243 |
| 00:19:02,200 --> 00:19:08,940 |
| time, we used X bar as the sample mean and mu as |
|
|
| 244 |
| 00:19:08,940 --> 00:19:14,460 |
| population mean. Also, S square as sample variance |
|
|
| 245 |
| 00:19:14,460 --> 00:19:18,740 |
| and sigma square as population variance. Here, R |
|
|
| 246 |
| 00:19:18,740 --> 00:19:24,360 |
| is used as sample coefficient of correlation and |
|
|
| 247 |
| 00:19:24,360 --> 00:19:29,420 |
| rho, this Greek letter pronounced as rho. Rho is |
|
|
| 248 |
| 00:19:29,420 --> 00:19:35,160 |
| used for population coefficient of correlation. |
|
|
| 249 |
| 00:19:37,640 --> 00:19:42,040 |
| There are some features of R or Rho. The first one |
|
|
| 250 |
| 00:19:42,040 --> 00:19:47,960 |
| is unity-free. R or Rho is unity-free. That means |
|
|
| 251 |
| 00:19:47,960 --> 00:19:54,900 |
| if X represents... |
|
|
| 252 |
| 00:19:54,900 --> 00:19:58,960 |
| And let's assume that the correlation between X |
|
|
| 253 |
| 00:19:58,960 --> 00:20:02,040 |
| and Y equals 0.75. |
|
|
| 254 |
| 00:20:04,680 --> 00:20:07,260 |
| Now, in this case, there is no unity. You cannot |
|
|
| 255 |
| 00:20:07,260 --> 00:20:13,480 |
| say 0.75 years or 0.75 kilograms. It's unity-free. |
|
|
| 256 |
| 00:20:13,940 --> 00:20:17,840 |
| There is no unit for the correlation coefficient, |
|
|
| 257 |
| 00:20:18,020 --> 00:20:21,120 |
| the same as Cv. If you remember Cv, the |
|
|
| 258 |
| 00:20:21,120 --> 00:20:24,320 |
| coefficient of correlation, also this one is unity |
|
|
| 259 |
| 00:20:24,320 --> 00:20:30,500 |
| -free. The second feature of R ranges between |
|
|
| 260 |
| 00:20:30,500 --> 00:20:36,740 |
| minus one and plus one. As I mentioned, R lies |
|
|
| 261 |
| 00:20:36,740 --> 00:20:42,340 |
| between minus one and plus one. Now, by using the |
|
|
| 262 |
| 00:20:42,340 --> 00:20:48,100 |
| value of R, you can determine two things. Number |
|
|
| 263 |
| 00:20:48,100 --> 00:20:53,360 |
| one, we can determine the direction. and strength |
|
|
| 264 |
| 00:20:53,360 --> 00:20:56,940 |
| by using the sign you can determine if there |
|
|
| 265 |
| 00:20:56,940 --> 00:21:03,980 |
| exists positive or negative so sign of R determine |
|
|
| 266 |
| 00:21:03,980 --> 00:21:08,040 |
| negative or positive relationship the direction |
|
|
| 267 |
| 00:21:08,040 --> 00:21:17,840 |
| the absolute value of R I mean absolute of R I |
|
|
| 268 |
| 00:21:17,840 --> 00:21:21,980 |
| mean ignore the sign So the absolute value of R |
|
|
| 269 |
| 00:21:21,980 --> 00:21:24,100 |
| determines the strength. |
|
|
| 270 |
| 00:21:27,700 --> 00:21:30,760 |
| So by using the sine of R, you can determine the |
|
|
| 271 |
| 00:21:30,760 --> 00:21:35,680 |
| direction, either positive or negative. By using |
|
|
| 272 |
| 00:21:35,680 --> 00:21:37,740 |
| the absolute value, you can determine the |
|
|
| 273 |
| 00:21:37,740 --> 00:21:43,500 |
| strength. We can split the strength into two |
|
|
| 274 |
| 00:21:43,500 --> 00:21:52,810 |
| parts, either strong, moderate, or weak. So weak, |
|
|
| 275 |
| 00:21:53,770 --> 00:21:59,130 |
| moderate, and strong by using the absolute value |
|
|
| 276 |
| 00:21:59,130 --> 00:22:03,870 |
| of R. The closer to minus one, if R is close to |
|
|
| 277 |
| 00:22:03,870 --> 00:22:07,010 |
| minus one, the stronger the negative relationship |
|
|
| 278 |
| 00:22:07,010 --> 00:22:09,430 |
| between X and Y. For example, imagine |
|
|
| 279 |
| 00:22:22,670 --> 00:22:26,130 |
| And as we mentioned, R ranges between minus 1 and |
|
|
| 280 |
| 00:22:26,130 --> 00:22:26,630 |
| plus 1. |
|
|
| 281 |
| 00:22:30,070 --> 00:22:35,710 |
| So if R is close to minus 1, it's a strong |
|
|
| 282 |
| 00:22:35,710 --> 00:22:41,250 |
| relationship. Strong linked relationship. The |
|
|
| 283 |
| 00:22:41,250 --> 00:22:45,190 |
| closer to 1, the stronger the positive |
|
|
| 284 |
| 00:22:45,190 --> 00:22:49,230 |
| relationship. I mean, if R is close. Strong |
|
|
| 285 |
| 00:22:49,230 --> 00:22:54,480 |
| positive. So strong in either direction, either to |
|
|
| 286 |
| 00:22:54,480 --> 00:22:57,640 |
| the left side or to the right side. Strong |
|
|
| 287 |
| 00:22:57,640 --> 00:23:00,280 |
| negative. On the other hand, there exists strong |
|
|
| 288 |
| 00:23:00,280 --> 00:23:05,940 |
| negative relationship. Positive. Positive. If R is |
|
|
| 289 |
| 00:23:05,940 --> 00:23:10,640 |
| close to zero, weak. Here we can say there exists |
|
|
| 290 |
| 00:23:10,640 --> 00:23:15,940 |
| weak relationship between X and Y. |
|
|
| 291 |
| 00:23:19,260 --> 00:23:25,480 |
| If R is close to 0.5 or |
|
|
| 292 |
| 00:23:25,480 --> 00:23:32,320 |
| minus 0.5, you can say there exists positive |
|
|
| 293 |
| 00:23:32,320 --> 00:23:38,840 |
| -moderate or negative-moderate relationship. So |
|
|
| 294 |
| 00:23:38,840 --> 00:23:42,200 |
| you can split or you can divide the strength of |
|
|
| 295 |
| 00:23:42,200 --> 00:23:44,540 |
| the relationship between X and Y into three parts. |
|
|
| 296 |
| 00:23:45,860 --> 00:23:50,700 |
| Strong, close to minus one of Plus one, weak, |
|
|
| 297 |
| 00:23:51,060 --> 00:23:59,580 |
| close to zero, moderate, close to 0.5. 0.5 is |
|
|
| 298 |
| 00:23:59,580 --> 00:24:04,580 |
| halfway between 0 and 1, and minus 0.5 is also |
|
|
| 299 |
| 00:24:04,580 --> 00:24:09,040 |
| halfway between minus 1 and 0. Now for example, |
|
|
| 300 |
| 00:24:09,920 --> 00:24:15,580 |
| what's about if R equals minus 0.5? Suppose R1 is |
|
|
| 301 |
| 00:24:15,580 --> 00:24:16,500 |
| minus 0.5. |
|
|
| 302 |
| 00:24:20,180 --> 00:24:27,400 |
| strong negative or equal minus point eight strong |
|
|
| 303 |
| 00:24:27,400 --> 00:24:33,540 |
| negative which is more strong nine nine because |
|
|
| 304 |
| 00:24:33,540 --> 00:24:39,670 |
| this value is close closer to minus one than Minus |
|
|
| 305 |
| 00:24:39,670 --> 00:24:44,070 |
| 0.8. Even this value is greater than minus 0.9, |
|
|
| 306 |
| 00:24:44,530 --> 00:24:50,870 |
| but minus 0.9 is close to minus 1, more closer to |
|
|
| 307 |
| 00:24:50,870 --> 00:24:56,910 |
| minus 1 than minus 0.8. On the other hand, if R |
|
|
| 308 |
| 00:24:56,910 --> 00:25:01,190 |
| equals 0.75, that means there exists positive |
|
|
| 309 |
| 00:25:01,190 --> 00:25:06,970 |
| relationship. If R equals 0.85, also there exists |
|
|
| 310 |
| 00:25:06,970 --> 00:25:13,540 |
| positive. But R2 is stronger than R1, because 0.85 |
|
|
| 311 |
| 00:25:13,540 --> 00:25:20,980 |
| is closer to plus 1 than 0.7. So we can say that |
|
|
| 312 |
| 00:25:20,980 --> 00:25:23,960 |
| there exists strong relationship between X and Y, |
|
|
| 313 |
| 00:25:24,020 --> 00:25:27,260 |
| and this relationship is positive. So again, by |
|
|
| 314 |
| 00:25:27,260 --> 00:25:32,530 |
| using the sign, you can tell the direction. The |
|
|
| 315 |
| 00:25:32,530 --> 00:25:35,910 |
| absolute value can tell the strength of the |
|
|
| 316 |
| 00:25:35,910 --> 00:25:39,870 |
| relationship between X and Y. So there are five |
|
|
| 317 |
| 00:25:39,870 --> 00:25:44,150 |
| features of R, unity-free. Ranges between minus |
|
|
| 318 |
| 00:25:44,150 --> 00:25:47,750 |
| one and plus one. Closer to minus one, it means |
|
|
| 319 |
| 00:25:47,750 --> 00:25:51,950 |
| stronger negative. Closer to plus one, stronger |
|
|
| 320 |
| 00:25:51,950 --> 00:25:56,410 |
| positive. Close to zero, it means there is no |
|
|
| 321 |
| 00:25:56,410 --> 00:26:00,790 |
| relationship. Or the weaker, the relationship |
|
|
| 322 |
| 00:26:00,790 --> 00:26:13,240 |
| between X and Y. By using scatter plots, we |
|
|
| 323 |
| 00:26:13,240 --> 00:26:18,160 |
| can construct a scatter plot by plotting the Y |
|
|
| 324 |
| 00:26:18,160 --> 00:26:24,060 |
| values versus the X values. Y in the vertical axis |
|
|
| 325 |
| 00:26:24,060 --> 00:26:28,400 |
| and X in the horizontal axis. If you look |
|
|
| 326 |
| 00:26:28,400 --> 00:26:34,500 |
| carefully at graph number one and three, We see |
|
|
| 327 |
| 00:26:34,500 --> 00:26:42,540 |
| that all the points lie on the straight line, |
|
|
| 328 |
| 00:26:44,060 --> 00:26:48,880 |
| either this way or the other way. If all the |
|
|
| 329 |
| 00:26:48,880 --> 00:26:52,320 |
| points lie on the straight line, it means they |
|
|
| 330 |
| 00:26:52,320 --> 00:26:56,970 |
| exist perfectly. not even strong it's perfect |
|
|
| 331 |
| 00:26:56,970 --> 00:27:02,710 |
| relationship either negative or positive so this |
|
|
| 332 |
| 00:27:02,710 --> 00:27:07,530 |
| one perfect negative negative |
|
|
| 333 |
| 00:27:07,530 --> 00:27:14,090 |
| because x increases y goes down decline so if x is |
|
|
| 334 |
| 00:27:14,090 --> 00:27:19,590 |
| for example five maybe y is supposed to twenty if |
|
|
| 335 |
| 00:27:19,590 --> 00:27:25,510 |
| x increased to seven maybe y is fifteen So if X |
|
|
| 336 |
| 00:27:25,510 --> 00:27:29,290 |
| increases, in this case, Y declines or decreases, |
|
|
| 337 |
| 00:27:29,850 --> 00:27:34,290 |
| it means there exists negative relationship. On |
|
|
| 338 |
| 00:27:34,290 --> 00:27:40,970 |
| the other hand, the left corner here, positive |
|
|
| 339 |
| 00:27:40,970 --> 00:27:44,710 |
| relationship, because X increases, Y also goes up. |
|
|
| 340 |
| 00:27:45,970 --> 00:27:48,990 |
| And perfect, because all the points lie on the |
|
|
| 341 |
| 00:27:48,990 --> 00:27:52,110 |
| straight line. So it's perfect, positive, perfect, |
|
|
| 342 |
| 00:27:52,250 --> 00:27:57,350 |
| negative relationship. So it's straightforward to |
|
|
| 343 |
| 00:27:57,350 --> 00:27:59,550 |
| determine if it's perfect by using scatterplot. |
|
|
| 344 |
| 00:28:02,230 --> 00:28:04,950 |
| Also, by scatterplot, you can tell the direction |
|
|
| 345 |
| 00:28:04,950 --> 00:28:09,270 |
| of the relationship. For the second scatterplot, |
|
|
| 346 |
| 00:28:09,630 --> 00:28:12,270 |
| it seems to be that there exists negative |
|
|
| 347 |
| 00:28:12,270 --> 00:28:13,730 |
| relationship between X and Y. |
|
|
| 348 |
| 00:28:16,850 --> 00:28:21,030 |
| In this one, also there exists a relationship |
|
|
| 349 |
| 00:28:24,730 --> 00:28:32,170 |
| positive which one is strong more strong this |
|
|
| 350 |
| 00:28:32,170 --> 00:28:37,110 |
| one is stronger because the points are close to |
|
|
| 351 |
| 00:28:37,110 --> 00:28:40,710 |
| the straight line much more than the other scatter |
|
|
| 352 |
| 00:28:40,710 --> 00:28:43,410 |
| plot so you can say there exists negative |
|
|
| 353 |
| 00:28:43,410 --> 00:28:45,810 |
| relationship but that one is stronger than the |
|
|
| 354 |
| 00:28:45,810 --> 00:28:49,550 |
| other one this one is positive but the points are |
|
|
| 355 |
| 00:28:49,550 --> 00:28:55,400 |
| scattered around the straight line so you can tell |
|
|
| 356 |
| 00:28:55,400 --> 00:29:00,000 |
| the direction and sometimes sometimes not all the |
|
|
| 357 |
| 00:29:00,000 --> 00:29:04,640 |
| time you can tell the strength sometimes it's very |
|
|
| 358 |
| 00:29:04,640 --> 00:29:07,960 |
| clear that the relation is strong if the points |
|
|
| 359 |
| 00:29:07,960 --> 00:29:11,480 |
| are very close straight line that means the |
|
|
| 360 |
| 00:29:11,480 --> 00:29:15,940 |
| relation is strong now the other one the last one |
|
|
| 361 |
| 00:29:15,940 --> 00:29:23,850 |
| here As X increases, Y stays at the same value. |
|
|
| 362 |
| 00:29:23,970 --> 00:29:29,450 |
| For example, if Y is 20 and X is 1. X is 1, Y is |
|
|
| 363 |
| 00:29:29,450 --> 00:29:33,870 |
| 20. X increases to 2, for example. Y is still 20. |
|
|
| 364 |
| 00:29:34,650 --> 00:29:37,230 |
| So that means there is no relationship between X |
|
|
| 365 |
| 00:29:37,230 --> 00:29:41,830 |
| and Y. It's a constant. Y equals a constant value. |
|
|
| 366 |
| 00:29:42,690 --> 00:29:50,490 |
| Whatever X is, Y will have constant value. So that |
|
|
| 367 |
| 00:29:50,490 --> 00:29:54,790 |
| means there is no relationship between X and Y. |
|
|
| 368 |
| 00:29:56,490 --> 00:30:01,850 |
| Let's see how can we compute the correlation |
|
|
| 369 |
| 00:30:01,850 --> 00:30:07,530 |
| between two variables. For example, suppose we |
|
|
| 370 |
| 00:30:07,530 --> 00:30:12,150 |
| have data for father's height and son's height. |
|
|
| 371 |
| 00:30:13,370 --> 00:30:16,510 |
| And we are interested to see if father's height |
|
|
| 372 |
| 00:30:16,510 --> 00:30:21,730 |
| affects his son's height. So we have data for 10 |
|
|
| 373 |
| 00:30:21,730 --> 00:30:28,610 |
| observations here. Father number one, his height |
|
|
| 374 |
| 00:30:28,610 --> 00:30:38,570 |
| is 64 inches. And you know that inch equals 2 |
|
|
| 375 |
| 00:30:38,570 --> 00:30:39,230 |
| .5. |
|
|
| 376 |
| 00:30:43,520 --> 00:30:52,920 |
| So X is 64, Sun's height is 65. X is 68, Sun's |
|
|
| 377 |
| 00:30:52,920 --> 00:30:58,820 |
| height is 67 and so on. Sometimes, if the dataset |
|
|
| 378 |
| 00:30:58,820 --> 00:31:02,600 |
| is small enough, as in this example, we have just |
|
|
| 379 |
| 00:31:02,600 --> 00:31:08,640 |
| 10 observations, you can tell the direction. I |
|
|
| 380 |
| 00:31:08,640 --> 00:31:12,060 |
| mean, you can say, yes, for this specific example, |
|
|
| 381 |
| 00:31:12,580 --> 00:31:15,280 |
| there exists positive relationship between x and |
|
|
| 382 |
| 00:31:15,280 --> 00:31:20,820 |
| y. But if the data set is large, it's very hard to |
|
|
| 383 |
| 00:31:20,820 --> 00:31:22,620 |
| figure out if the relation is positive or |
|
|
| 384 |
| 00:31:22,620 --> 00:31:26,400 |
| negative. So we have to find or to compute the |
|
|
| 385 |
| 00:31:26,400 --> 00:31:29,700 |
| coefficient of correlation in order to see there |
|
|
| 386 |
| 00:31:29,700 --> 00:31:32,940 |
| exists positive, negative, strong, weak, or |
|
|
| 387 |
| 00:31:32,940 --> 00:31:37,820 |
| moderate. but again you can tell from this simple |
|
|
| 388 |
| 00:31:37,820 --> 00:31:40,280 |
| example yes there is a positive relationship |
|
|
| 389 |
| 00:31:40,280 --> 00:31:44,660 |
| because just if you pick random numbers here for |
|
|
| 390 |
| 00:31:44,660 --> 00:31:49,240 |
| example 64 father's height his son's height 65 if |
|
|
| 391 |
| 00:31:49,240 --> 00:31:54,600 |
| we move up here to 70 for father's height his |
|
|
| 392 |
| 00:31:54,600 --> 00:32:00,160 |
| son's height is going to be 72 so as father |
|
|
| 393 |
| 00:32:00,160 --> 00:32:05,020 |
| heights increases Also, son's height increases. |
|
|
| 394 |
| 00:32:06,320 --> 00:32:11,700 |
| For example, 77, father's height. His son's height |
|
|
| 395 |
| 00:32:11,700 --> 00:32:15,160 |
| is 76. So that means there exists positive |
|
|
| 396 |
| 00:32:15,160 --> 00:32:19,740 |
| relationship. Make sense? But again, for large |
|
|
| 397 |
| 00:32:19,740 --> 00:32:20,780 |
| data, you cannot tell that. |
|
|
| 398 |
| 00:32:31,710 --> 00:32:36,090 |
| If, again, by using this data, small data, you can |
|
|
| 399 |
| 00:32:36,090 --> 00:32:40,730 |
| determine just the length, the strength, I'm |
|
|
| 400 |
| 00:32:40,730 --> 00:32:43,490 |
| sorry, the strength of a relationship or the |
|
|
| 401 |
| 00:32:43,490 --> 00:32:47,590 |
| direction of the relationship. Just pick any |
|
|
| 402 |
| 00:32:47,590 --> 00:32:51,030 |
| number at random. For example, if we pick this |
|
|
| 403 |
| 00:32:51,030 --> 00:32:51,290 |
| number. |
|
|
| 404 |
| 00:32:55,050 --> 00:33:00,180 |
| Father's height is 68, his son's height is 70. Now |
|
|
| 405 |
| 00:33:00,180 --> 00:33:02,180 |
| suppose we pick another number that is greater |
|
|
| 406 |
| 00:33:02,180 --> 00:33:05,840 |
| than 68, then let's see what will happen. For |
|
|
| 407 |
| 00:33:05,840 --> 00:33:11,060 |
| father's height 70, his son's height increases up |
|
|
| 408 |
| 00:33:11,060 --> 00:33:17,160 |
| to 72. Similarly, 72 father's height, his son's |
|
|
| 409 |
| 00:33:17,160 --> 00:33:22,060 |
| height 75. So that means X increases, Y also |
|
|
| 410 |
| 00:33:22,060 --> 00:33:25,740 |
| increases. So that means there exists both of |
|
|
| 411 |
| 00:33:25,740 --> 00:33:32,570 |
| them. For sure it is hard to tell this direction |
|
|
| 412 |
| 00:33:32,570 --> 00:33:36,130 |
| if the data is large. Because maybe you will find |
|
|
| 413 |
| 00:33:36,130 --> 00:33:40,250 |
| as X increases for one point, Y maybe decreases |
|
|
| 414 |
| 00:33:40,250 --> 00:33:43,610 |
| for that point. So it depends on the data you |
|
|
| 415 |
| 00:33:43,610 --> 00:33:49,010 |
| have. Anyway, let's see how can we compute R. I |
|
|
| 416 |
| 00:33:49,010 --> 00:33:53,770 |
| will use Excel to show how can we do these |
|
|
| 417 |
| 00:33:53,770 --> 00:33:54,550 |
| calculations. |
|
|
| 418 |
| 00:34:02,110 --> 00:34:06,530 |
| The screen is clear. But give me the data of X and |
|
|
| 419 |
| 00:34:06,530 --> 00:34:06,750 |
| Y. |
|
|
| 420 |
| 00:34:10,710 --> 00:34:14,310 |
| X is 64. 68. |
|
|
| 421 |
| 00:34:18,910 --> 00:34:26,830 |
| 68. 78. There is one 68. 78. 74. |
|
|
| 422 |
| 00:34:31,120 --> 00:34:37,600 |
| Seventy-four. Seventy-five. Seventy-six. |
|
|
| 423 |
| 00:34:38,360 --> 00:34:42,240 |
| Seventy-seven. Seventy-five. So that's the values |
|
|
| 424 |
| 00:34:42,240 --> 00:34:49,440 |
| of X, Y values. Seventy. Seventy-five. Seventy |
|
|
| 425 |
| 00:34:49,440 --> 00:34:49,800 |
| -seven. |
|
|
| 426 |
| 00:35:17,230 --> 00:35:23,730 |
| So first we have to compute it. x times y so |
|
|
| 427 |
| 00:35:23,730 --> 00:35:28,270 |
| that's as x times |
|
|
| 428 |
| 00:35:28,270 --> 00:35:38,230 |
| the value of y so 46 times 65 equals 4160 x |
|
|
| 429 |
| 00:35:38,230 --> 00:35:46,050 |
| squared so this value squared for y squared 65 |
|
|
| 430 |
| 00:35:48,660 --> 00:35:53,700 |
| Square and we have to do this one for the rest of |
|
|
| 431 |
| 00:35:53,700 --> 00:36:03,160 |
| the data So |
|
|
| 432 |
| 00:36:03,160 --> 00:36:07,600 |
| that's the sum of XY sum X squared and Y squared |
|
|
| 433 |
| 00:36:07,600 --> 00:36:13,480 |
| now the summation So |
|
|
| 434 |
| 00:36:13,480 --> 00:36:17,180 |
| that's the sum of X and Y |
|
|
| 435 |
| 00:36:20,380 --> 00:36:27,040 |
| We have to compute the mean of x and y. So that is |
|
|
| 436 |
| 00:36:27,040 --> 00:36:31,380 |
| this sum divided by n, where n is 10 in this case. |
|
|
| 437 |
| 00:36:34,600 --> 00:36:36,100 |
| So this is the first step. |
|
|
| 438 |
| 00:36:41,820 --> 00:36:48,900 |
| Let's see how can we compute R. R, we have sum of |
|
|
| 439 |
| 00:36:48,900 --> 00:37:00,780 |
| x, y. minus n is 10 times x bar times y bar. This |
|
|
| 440 |
| 00:37:00,780 --> 00:37:03,100 |
| is the first quantity. The other one is square |
|
|
| 441 |
| 00:37:03,100 --> 00:37:08,580 |
| root of sum |
|
|
| 442 |
| 00:37:08,580 --> 00:37:15,420 |
| x squared minus n x bar squared. |
|
|
| 443 |
| 00:37:18,830 --> 00:37:24,770 |
| times some y squared minus n times y bar squared. |
|
|
| 444 |
| 00:37:28,930 --> 00:37:34,090 |
| And we have to find the square root of this value. |
|
|
| 445 |
| 00:37:34,210 --> 00:37:40,810 |
| So square root, that will give this result. So now |
|
|
| 446 |
| 00:37:40,810 --> 00:37:46,990 |
| R equals this value divided by |
|
|
| 447 |
| 00:37:49,670 --> 00:37:54,890 |
| 155 and round always to two decimal places will |
|
|
| 448 |
| 00:37:54,890 --> 00:38:05,590 |
| give 87 so r is 87 so first step we have x and y |
|
|
| 449 |
| 00:38:05,590 --> 00:38:12,470 |
| compute xy x squared y squared sum of these all of |
|
|
| 450 |
| 00:38:12,470 --> 00:38:18,100 |
| these then x bar y bar values are given Then just |
|
|
| 451 |
| 00:38:18,100 --> 00:38:20,820 |
| use the formula you have, we'll get R to be at |
|
|
| 452 |
| 00:38:20,820 --> 00:38:31,540 |
| seven. So in this case, if we just go back to |
|
|
| 453 |
| 00:38:31,540 --> 00:38:33,400 |
| the slide we have here. |
|
|
| 454 |
| 00:38:36,440 --> 00:38:41,380 |
| As we mentioned, father's height is the |
|
|
| 455 |
| 00:38:41,380 --> 00:38:45,640 |
| explanatory variable. Son's height is the response |
|
|
| 456 |
| 00:38:45,640 --> 00:38:46,060 |
| variable. |
|
|
| 457 |
| 00:38:49,190 --> 00:38:52,810 |
| And that simple calculation gives summation of xi, |
|
|
| 458 |
| 00:38:54,050 --> 00:38:57,810 |
| summation of yi, summation x squared, y squared, |
|
|
| 459 |
| 00:38:57,970 --> 00:39:02,690 |
| and some xy. And finally, we'll get that result, |
|
|
| 460 |
| 00:39:02,850 --> 00:39:07,850 |
| 87%. Now, the sign is positive. That means there |
|
|
| 461 |
| 00:39:07,850 --> 00:39:13,960 |
| exists positive. And 0.87 is close to 1. That |
|
|
| 462 |
| 00:39:13,960 --> 00:39:17,320 |
| means there exists strong positive relationship |
|
|
| 463 |
| 00:39:17,320 --> 00:39:22,480 |
| between father's and son's height. I think the |
|
|
| 464 |
| 00:39:22,480 --> 00:39:25,060 |
| calculation is straightforward. |
|
|
| 465 |
| 00:39:27,280 --> 00:39:33,280 |
| Now, for this example, the data are given in |
|
|
| 466 |
| 00:39:33,280 --> 00:39:37,460 |
| inches. I mean father's and son's height in inch. |
|
|
| 467 |
| 00:39:38,730 --> 00:39:41,050 |
| Suppose we want to convert from inch to |
|
|
| 468 |
| 00:39:41,050 --> 00:39:44,750 |
| centimeter, so we have to multiply by 2. Do you |
|
|
| 469 |
| 00:39:44,750 --> 00:39:52,050 |
| think in this case, R will change? So if we add or |
|
|
| 470 |
| 00:39:52,050 --> 00:39:59,910 |
| multiply or divide, R will not change? I mean, if |
|
|
| 471 |
| 00:39:59,910 --> 00:40:06,880 |
| we have X values, And we divide or multiply X, I |
|
|
| 472 |
| 00:40:06,880 --> 00:40:09,460 |
| mean each value of X, by a number, by a fixed |
|
|
| 473 |
| 00:40:09,460 --> 00:40:12,600 |
| value. For example, suppose here we multiplied |
|
|
| 474 |
| 00:40:12,600 --> 00:40:19,460 |
| each value by 2.5 for X. Also multiply Y by the |
|
|
| 475 |
| 00:40:19,460 --> 00:40:24,520 |
| same value, 2.5. Y will be the same. In addition |
|
|
| 476 |
| 00:40:24,520 --> 00:40:28,920 |
| to that, if we multiply X by 2.5, for example, and |
|
|
| 477 |
| 00:40:28,920 --> 00:40:34,960 |
| Y by 5, also R will not change. But you have to be |
|
|
| 478 |
| 00:40:34,960 --> 00:40:39,400 |
| careful. We multiply each value of x by the same |
|
|
| 479 |
| 00:40:39,400 --> 00:40:45,700 |
| number. And each value of y by the same number, |
|
|
| 480 |
| 00:40:45,820 --> 00:40:49,640 |
| that number may be different from x. So I mean |
|
|
| 481 |
| 00:40:49,640 --> 00:40:56,540 |
| multiply x by 2.5 and y by minus 1 or plus 2 or |
|
|
| 482 |
| 00:40:56,540 --> 00:41:01,000 |
| whatever you have. But if it's negative, then |
|
|
| 483 |
| 00:41:01,000 --> 00:41:05,640 |
| we'll get negative answer. I mean if Y is |
|
|
| 484 |
| 00:41:05,640 --> 00:41:08,060 |
| positive, for example, and we multiply each value |
|
|
| 485 |
| 00:41:08,060 --> 00:41:13,000 |
| Y by minus one, that will give negative sign. But |
|
|
| 486 |
| 00:41:13,000 --> 00:41:17,640 |
| here I meant if we multiply this value by positive |
|
|
| 487 |
| 00:41:17,640 --> 00:41:21,320 |
| sign, plus two, plus three, and let's see how can |
|
|
| 488 |
| 00:41:21,320 --> 00:41:22,540 |
| we do that by Excel. |
|
|
| 489 |
| 00:41:26,320 --> 00:41:31,480 |
| Now this is the data we have. I just make copy. |
|
|
| 490 |
| 00:41:37,730 --> 00:41:45,190 |
| I will multiply each value X by 2.5. And I will do |
|
|
| 491 |
| 00:41:45,190 --> 00:41:49,590 |
| the same for Y |
|
|
| 492 |
| 00:41:49,590 --> 00:41:57,190 |
| value. I will replace this data by the new one. |
|
|
| 493 |
| 00:41:58,070 --> 00:42:00,410 |
| For sure the calculations will, the computations |
|
|
| 494 |
| 00:42:00,410 --> 00:42:09,740 |
| here will change, but R will stay the same. So |
|
|
| 495 |
| 00:42:09,740 --> 00:42:14,620 |
| here we multiply each x by 2.5 and the same for y. |
|
|
| 496 |
| 00:42:15,540 --> 00:42:19,400 |
| The calculations here are different. We have |
|
|
| 497 |
| 00:42:19,400 --> 00:42:22,960 |
| different sum, different sum of x, sum of y and so |
|
|
| 498 |
| 00:42:22,960 --> 00:42:31,040 |
| on, but are the same. Let's see if we multiply |
|
|
| 499 |
| 00:42:31,040 --> 00:42:38,880 |
| just x by 2.5 and y the same. |
|
|
| 500 |
| 00:42:41,840 --> 00:42:49,360 |
| So we multiplied x by 2.5 and we keep it make |
|
|
| 501 |
| 00:42:49,360 --> 00:42:57,840 |
| sense? Now let's see how outliers will affect the |
|
|
| 502 |
| 00:42:57,840 --> 00:43:03,260 |
| value of R. Let's say if we change one point in |
|
|
| 503 |
| 00:43:03,260 --> 00:43:08,480 |
| the data set support. I just changed 64. |
|
|
| 504 |
| 00:43:13,750 --> 00:43:24,350 |
| for example if just by typo and just enter 6 so it |
|
|
| 505 |
| 00:43:24,350 --> 00:43:33,510 |
| was 87 it becomes 0.7 so there is a big difference |
|
|
| 506 |
| 00:43:33,510 --> 00:43:38,670 |
| between 0.87 and 0.7 and just we change one value |
|
|
| 507 |
| 00:43:38,670 --> 00:43:45,920 |
| now suppose the other one is zero 82. The other is |
|
|
| 508 |
| 00:43:45,920 --> 00:43:48,260 |
| 2, for example. 1. |
|
|
| 509 |
| 00:43:53,380 --> 00:43:59,200 |
| I just changed half of the data. Now R was 87, it |
|
|
| 510 |
| 00:43:59,200 --> 00:44:02,920 |
| becomes 59. That means these outliers, these |
|
|
| 511 |
| 00:44:02,920 --> 00:44:06,180 |
| values for sure are outliers and they fit the |
|
|
| 512 |
| 00:44:06,180 --> 00:44:07,060 |
| correlation coefficient. |
|
|
| 513 |
| 00:44:11,110 --> 00:44:14,970 |
| Now let's see if we just change this 1 to be 200. |
|
|
| 514 |
| 00:44:15,870 --> 00:44:20,430 |
| It will go from 50 to up to 63. That means any |
|
|
| 515 |
| 00:44:20,430 --> 00:44:26,010 |
| changes in x or y values will change the y. But if |
|
|
| 516 |
| 00:44:26,010 --> 00:44:30,070 |
| we add or multiply all the values by a constant, r |
|
|
| 517 |
| 00:44:30,070 --> 00:44:31,170 |
| will stay the same. |
|
|
| 518 |
| 00:44:35,250 --> 00:44:43,590 |
| Any questions? That's the end of chapter 3. I will |
|
|
| 519 |
| 00:44:43,590 --> 00:44:48,990 |
| move quickly to the practice problems we have. And |
|
|
| 520 |
| 00:44:48,990 --> 00:44:55,270 |
| we posted the practice in the course website. |
|
|
|
|