"""
We shall say that an n-digit number is pandigital if it makes use of all the
digits 1 to n exactly once; for example, the 5-digit number, 15234, is 1 through
5 pandigital.

The product 7254 is unusual, as the identity, 39 × 186 = 7254, containing
multiplicand, multiplier, and product is 1 through 9 pandigital.

Find the sum of all products whose multiplicand/multiplier/product identity can
be written as a 1 through 9 pandigital.

HINT: Some products can be obtained in more than one way so be sure to only
include it once in your sum.
"""
import itertools


def isCombinationValid(combination):
    """
    Checks if a combination (a tuple of 9 digits)
    is a valid product equation.

    >>> isCombinationValid(('3', '9', '1', '8', '6', '7', '2', '5', '4'))
    True

    >>> isCombinationValid(('1', '2', '3', '4', '5', '6', '7', '8', '9'))
    False

    """
    return (
        int(''.join(combination[0:2])) *
        int(''.join(combination[2:5])) ==
        int(''.join(combination[5:9]))
    ) or (
        int(''.join(combination[0])) *
        int(''.join(combination[1:5])) ==
        int(''.join(combination[5:9]))
    )


def solution():
    """
    Finds the sum of all products whose multiplicand/multiplier/product identity
    can be written as a 1 through 9 pandigital

    >>> solution()
    45228
    """

    return sum(
        set(
            [
                int(''.join(pandigital[5:9]))
                for pandigital
                in itertools.permutations('123456789')
                if isCombinationValid(pandigital)
            ]
        )
    )

if __name__ == "__main__":
    print(solution())

Add problem 32 solution (#1257)