# Given an array of ints, return the sum of the first 2 elements in the array.
# If the array length is less than 2, just sum up the elements that exist,
# returning 0 if the array is length 0. 

# sum2([1, 2, 3]) -> 3
# sum2([1, 1]) -> 2
# sum2([1, 1, 1, 1]) -> 2

def sum2(nums):
  return sum(nums[0:2])

print(sum2([1, 2, 3]))
print(sum2([1, 1]))
print(sum2([1, 1, 1, 1]))

# Given an array of ints, return the sum of the first 2 elements in the array.
# If the array length is less than 2, just sum up the elements that exist,
# returning 0 if the array is length 0. 

# sum2([1, 2, 3]) --> 3
# sum2([1, 1]) --> 2
# sum2([1, 1, 1, 1]) --> 2

def sum2(nums):
  return sum(nums[0:2])

print(sum2([1, 2, 3]))
print(sum2([1, 1]))
print(sum2([1, 1, 1, 1]))

Update sum2.py