old_contents: # -*- coding: utf-8 -*-
  """
      flask-rstblog
      ~~~~~~~~~~~~~
  
      :copyright: (c) 2011 by Christoph Heer.
      :license: BSD, see LICENSE for more details.
  """
  
  from flask import Flask, url_for
  
  app = Flask("flaskrst")
  
  @app.context_processor
  def inject_navigation():
      navigation = []
      for item in app.config.get('NAVIGATION', []):
          kwargs = item.copy()
          del kwargs['route']
          del kwargs['name']
          
          link = url_for(item['route'], **kwargs)
          navigation.append((link, item['name']))
          
      return dict(navigation=navigation)
new_contents: # -*- coding: utf-8 -*-
  """
      flask-rstblog
      ~~~~~~~~~~~~~
  
      :copyright: (c) 2011 by Christoph Heer.
      :license: BSD, see LICENSE for more details.
  """
  
  from flask import Flask, url_for
  
  app = Flask("flaskrst")
  
  @app.context_processor
  def inject_navigation():
      navigation = []
      for item in app.config.get('NAVIGATION', []):
          if item.has_key('route') and item.has_key('label'):
              kwargs = item.copy()
              del kwargs['route']
              del kwargs['label']
          
              link = url_for(item['route'], **kwargs)
              navigation.append((link, item['label']))
          elif item.has_key('url') and item.has_key('label'):
              navigation.append((item['url'], item['label']))
  
      return dict(navigation=navigation)
subject: Rename navigation config key name to label and add support for links to external sites over the url key name