old_contents: # Licensed under a 3-clause BSD style license - see LICENSE.rst
  from __future__ import (absolute_import, division, print_function,
                          unicode_literals)
  import numpy as np
  from .check_random_state import check_random_state
  
  
  __all__ = ['random_cmap']
  
  
  def random_cmap(ncolors=256, background_color='black', random_state=None):
      """
      Generate a matplotlib colormap consisting of random (muted) colors.
  
      A random colormap is very useful for plotting segmentation images.
  
      Parameters
      ----------
      ncolors : int, optional
          The number of colors in the colormap.  For use with segmentation
          images, ``ncolors`` should be set to the number of labels.  The
          default is 256.
  
      background_color : str, optional
          The name of the background (first) color in the colormap.  Valid
          colors names are defined by ``matplotlib.colors.cnames``.  The
          default is ``'black'``.
  
      random_state : int or `~numpy.random.RandomState`, optional
          The pseudo-random number generator state used for random
          sampling.  Separate function calls with the same
          ``random_state`` will generate the same colormap.
  
      Returns
      -------
      cmap : `matplotlib.colors.Colormap`
          The matplotlib colormap with random colors.
      """
  
      from matplotlib import colors
  
      prng = check_random_state(random_state)
      h = prng.uniform(low=0.0, high=1.0, size=ncolors)
      s = prng.uniform(low=0.2, high=0.7, size=ncolors)
      v = prng.uniform(low=0.5, high=1.0, size=ncolors)
      hsv = np.transpose(np.array([h, s, v]))
      rgb = colors.hsv_to_rgb(hsv)
  
      if background_color is not None:
          if background_color not in colors.cnames:
              raise ValueError('"{0}" is not a valid background color '
                               'name'.format(background_color))
          rgb[0] = colors.hex2color(colors.cnames[background_color])
  
      return colors.ListedColormap(rgb)
  
new_contents: # Licensed under a 3-clause BSD style license - see LICENSE.rst
  from __future__ import (absolute_import, division, print_function,
                          unicode_literals)
  import numpy as np
  from .check_random_state import check_random_state
  
  
  __all__ = ['random_cmap']
  
  
  def random_cmap(ncolors=256, background_color='black', random_state=None):
      """
      Generate a matplotlib colormap consisting of random (muted) colors.
  
      A random colormap is very useful for plotting segmentation images.
  
      Parameters
      ----------
      ncolors : int, optional
          The number of colors in the colormap.  For use with segmentation
          images, ``ncolors`` should be set to the number of labels.  The
          default is 256.
  
      background_color : str, optional
          The name of the background (first) color in the colormap.  Valid
          colors names are defined by ``matplotlib.colors.cnames``.  The
          default is ``'black'``.
  
      random_state : int or `~numpy.random.RandomState`, optional
          The pseudo-random number generator state used for random
          sampling.  Separate function calls with the same
          ``random_state`` will generate the same colormap.
  
      Returns
      -------
      cmap : `matplotlib.colors.Colormap`
          The matplotlib colormap with random colors.
      """
  
      from matplotlib import colors
  
      prng = check_random_state(random_state)
      h = prng.uniform(low=0.0, high=1.0, size=ncolors)
      s = prng.uniform(low=0.2, high=0.7, size=ncolors)
      v = prng.uniform(low=0.5, high=1.0, size=ncolors)
      hsv = np.dstack((h, s, v))
      rgb = np.squeeze(colors.hsv_to_rgb(hsv))
  
      if background_color is not None:
          if background_color not in colors.cnames:
              raise ValueError('"{0}" is not a valid background color '
                               'name'.format(background_color))
          rgb[0] = colors.hex2color(colors.cnames[background_color])
  
      return colors.ListedColormap(rgb)
  
subject: Modify random_cmap to work with matplotlib 1.3