old_contents: """Leetcode 412. Fizz Buzz
  Easy
  
  URL: https://leetcode.com/problems/fizz-buzz/
  
  Write a program that outputs the string representation of numbers from 1 to n.
  
  But for multiples of three it should output "Fizz" instead of the number and
  for the multiples of five output "Buzz".
  For numbers which are multiples of both three and five output "FizzBuzz".
  
  Example:
  n = 15,
  Return:
  [
      "1",
      "2",
      "Fizz",
      "4",
      "Buzz",
      "Fizz",
      "7",
      "8",
      "Fizz",
      "Buzz",
      "11",
      "Fizz",
      "13",
      "14",
      "FizzBuzz"
  ]
  """
  
  class Solution(object):
      def fizzBuzz(self, n):
          """
          :type n: int
          :rtype: List[str]
          """
          fizzbuzz = [None] * n
  
          for i in range(1, n + 1):
              if i % 15 == 0:
                  fizzbuzz[i - 1] = "FizzBuzz"
              elif i % 3 == 0:
                  fizzbuzz[i - 1] = "Fizz"
              elif i % 5 == 0:
                  fizzbuzz[i - 1] = "Buzz"
              else:
                  fizzbuzz[i - 1] = str(i)
  
          return fizzbuzz
  
  
  def main():
      n = 15
      print Solution().fizzBuzz(n)
  
  
  if __name__ == '__main__':
      main()
  
new_contents: """Leetcode 412. Fizz Buzz
  Easy
  
  URL: https://leetcode.com/problems/fizz-buzz/
  
  Write a program that outputs the string representation of numbers from 1 to n.
  
  But for multiples of three it should output "Fizz" instead of the number and
  for the multiples of five output "Buzz".
  For numbers which are multiples of both three and five output "FizzBuzz".
  
  Example:
  n = 15,
  Return:
  [
      "1",
      "2",
      "Fizz",
      "4",
      "Buzz",
      "Fizz",
      "7",
      "8",
      "Fizz",
      "Buzz",
      "11",
      "Fizz",
      "13",
      "14",
      "FizzBuzz"
  ]
  """
  
  class Solution(object):
      def fizzBuzz(self, n):
          """
          :type n: int
          :rtype: List[str]
  
          Time complexity: O(n).
          Space complexity: O(1).
          """
          fizzbuzz = [None] * n
  
          for i in range(1, n + 1):
              if i % 15 == 0:
                  fizzbuzz[i - 1] = "FizzBuzz"
              elif i % 3 == 0:
                  fizzbuzz[i - 1] = "Fizz"
              elif i % 5 == 0:
                  fizzbuzz[i - 1] = "Buzz"
              else:
                  fizzbuzz[i - 1] = str(i)
  
          return fizzbuzz
  
  
  def main():
      n = 15
      print Solution().fizzBuzz(n)
  
  
  if __name__ == '__main__':
      main()
  
subject: Add time/space complexity