old_contents: """All helpers for the URL."""
  
  import urllib2
  
  from mimetypes import MimeTypes
  
  from ..base import FORMAT
  from ..exceptions import URLError
  
  
  def check_url(url):
      """
      Check if URL is accessible and what data format it is.
  
      Parameters
      ----------
      url : str
          URL to check.
  
      Returns
      -------
      str
          Data format of the URL.
      """
      dataformat = None
      response = None
      errors = []
  
      try:
          response = urllib2.urlopen(url)
  
          #if response.headers.get('Access-Control-Allow-Origin') != '*':
          #    errors.append(
          #        'The server does not allow to use this URL externally. Make '
          #        'sure that CORS is enabled on the server.'
          #    )
          #else:
          # Try to guess content type first
          content_type = MimeTypes().guess_type(url)[0]
  
          # If unsuccessful, get it from the headers
          if content_type is None:
              content_type = response.headers.get('Content-Type')
  
          if 'application/json' or 'application/vnd.geo+json' in content_type:
              dataformat = FORMAT.GeoJSON
          elif 'application/vnd.google-earth.kml+xml' in content_type:
              dataformat = FORMAT.KML
          else:
              errors.append('This data format is currently not supported.')
      except urllib2.URLError as error:
          if hasattr(error, 'code'):
              errors.append('The server returned %s error.' % error.code)
          if hasattr(error, 'reason'):
              errors.append('Failed to reach the server: %s.' % error.reason)
  
      if errors:
          raise URLError('The URL cannot be used due to:', errors)
  
      return dataformat
  
new_contents: """All helpers for the URL."""
  
  import urllib2
  
  from mimetypes import MimeTypes
  
  from ..base import FORMAT
  from ..exceptions import URLError
  
  
  def check_url(url):
      """
      Check if URL is accessible and what data format it is.
  
      Parameters
      ----------
      url : str
          URL to check.
  
      Returns
      -------
      str
          Data format of the URL.
      """
      dataformat = None
      response = None
      errors = []
  
      try:
          response = urllib2.urlopen(url)
  
          if response.headers.get('Access-Control-Allow-Origin') != '*':
              errors.append(
                  'The server does not allow to use this URL externally. Make '
                  'sure that CORS is enabled on the server.'
              )
          else:
              # Try to guess content type first
              content_type = MimeTypes().guess_type(url)[0]
  
              # If unsuccessful, get it from the headers
              if content_type is None:
                  content_type = response.headers.get('Content-Type')
  
              if 'application/json' in content_type:
                  dataformat = FORMAT.GeoJSON
              elif 'application/vnd.google-earth.kml+xml' in content_type:
                  dataformat = FORMAT.KML
              else:
                  errors.append('This data format is currently not supported.')
      except urllib2.URLError as error:
          if hasattr(error, 'code'):
              errors.append('The server returned %s error.' % error.code)
          if hasattr(error, 'reason'):
              errors.append('Failed to reach the server: %s.' % error.reason)
  
      if errors:
          raise URLError('The URL cannot be used due to:', errors)
  
      return dataformat
  
subject: Revert "Access-Control-Allow-Origin comment out"