new_contents: # Author: Param Singh <paramsingh258@gmail.com>
  import math
  
  def power_of_two(a):
      x = math.log(a, 2)
      return x == math.ceil(x)
  
  terms = int(raw_input())
  for _ in range(terms):
      a, b = map(int, raw_input().split())
      count = 0
      while not power_of_two(a) and a != 1:
          a /= 2
          count += 1 
      while a != b:
          if a > b:
              a /= 2;
          else:
              a *= 2
          count += 1
      print count
      
  
  
subject: Solve COOKMACH