new_contents: #!/usr/bin/env python
  #-*-coding:utf-8-*-
  
  '''
  The fraction 49/98 is a curious fraction, as an inexperienced
  mathematician in attempting to simplify it may incorrectly believe
  that 49/98 = 4/8, which is correct, is obtained by cancelling the 9s.
  
  We shall consider fractions like, 30/50 = 3/5, to be trivial examples.
  
  There are exactly four non-trivial examples of this type of fraction,
  less than one in value, and containing two digits in the numerator and denominator.
  
  If the product of these four fractions is given in its lowest common terms,
  find the value of the denominator.
  '''
  
  from fractions import Fraction
  from operator import mul
  import timeit
  
  
  def calc():
      fracs = {}
      for i in range(10, 100):
          if len(set(str(i))) == 1: continue
          for j in range(i, 100):
              if len(set(str(j))) == 1: continue
              if (str(i))[0] == (str(j))[1]:
                  if float((str(i))[1])/float((str(j))[0]) == float(i)/j:
                      fracs[i] = j
              elif (str(i))[1] == (str(j))[0]:
                  if (str(j))[1] == '0': continue
                  if float((str(i))[0])/float((str(j))[1]) == float(i)/j:
                      fracs[i] = j
      return Fraction(reduce(mul, fracs.keys()), reduce(mul, fracs.values())).denominator
  
  
  if __name__ == '__main__':
      print calc()
      print timeit.Timer('problem_033.calc()', 'import problem_033').timeit(10)
  
subject: add problem 33