new_contents: #!/bin/python3
  
  import itertools
  import collections
  
  def sliding_window(n, seq):
      """
      Copied from toolz
      https://toolz.readthedocs.io/en/latest/_modules/toolz/itertoolz.html#sliding_window
  
      A sequence of overlapping subsequences
  
      >>> list(sliding_window(2, [1, 2, 3, 4]))
      [(1, 2), (2, 3), (3, 4)]
  
      This function creates a sliding window suitable for transformations like
      sliding means / smoothing
  
      >>> mean = lambda seq: float(sum(seq)) / len(seq)
      >>> list(map(mean, sliding_window(2, [1, 2, 3, 4])))
      [1.5, 2.5, 3.5]
      """
      return zip(*(collections.deque(itertools.islice(it, i), 0) or it
                 for i, it in enumerate(itertools.tee(seq, n))))
  
  def birthday_chocolate(squares, day, month):
      birthday_chocolates = 0
      for piece in sliding_window(month, squares):
          if sum(piece) == day:
              birthday_chocolates += 1
      return birthday_chocolates
  
  _ = int(input().strip())
  SQUARES = list(map(int, input().strip().split(' ')))
  DAY, MONTH = map(int, input().strip().split(' '))
  print(birthday_chocolate(SQUARES, DAY, MONTH))
  
subject: Solve birthday chocolate