new_contents: # Source: https://gist.github.com/kmonsoor/2a1afba4ee127cce50a0
  
  try:
      # python 3
      from urllib.parse import urlparse, parse_qs
  except ImportError:
      # python 2
      from urlparse import urlparse, parse_qs
  
  
  def get_yt_video_id(url):
      """Returns Video_ID extracting from the given url of Youtube
  
      Examples of URLs:
        Valid:
          'http://youtu.be/_lOT2p_FCvA',
          'www.youtube.com/watch?v=_lOT2p_FCvA&feature=feedu',
          'http://www.youtube.com/embed/_lOT2p_FCvA',
          'http://www.youtube.com/v/_lOT2p_FCvA?version=3&amp;hl=en_US',
          'https://www.youtube.com/watch?v=rTHlyTphWP0&index=6&list=PLjeDyYvG6-40qawYNR4juzvSOg-ezZ2a6',
          'youtube.com/watch?v=_lOT2p_FCvA',
          'https://www.youtube.com/watch?v=S6q41Rfltsk'
  
        Invalid:
          'youtu.be/watch?v=_lOT2p_FCvA',
      """
  
      if url.startswith(('youtu', 'www')):
          url = 'http://' + url
  
      query = urlparse(url)
  
      if 'youtube' in query.hostname:
          if query.path == '/watch':
              return parse_qs(query.query)['v'][0]
          elif query.path.startswith(('/embed/', '/v/')):
              return query.path.split('/')[2]
      elif 'youtu.be' in query.hostname:
          return query.path[1:]
      else:
          raise ValueError
  
subject: Create get_youtube_video_id.py