old_contents: #Python reminders
  
  # Collapse the list for output
  ''.join(list)
  
  #Flatten list of lists
  flat_list = [item for subitem in lists for item in subitem]
  
  #Exammple for checking list for single digit (string)
  def checker(string):
  	print("Boom!" if "7" in str(string) else "there is no 7 in the list")
  checker([2, 55, 60, 97, 86, 3, 4, 6, 6])
  
  #Scan list for longest string and print max item
  print(max(len(i) for i in string.split()))
  
  #search for highest index of substring
  string.rindex(substring) -- If not found, raises exception
  string.rfind(substring) -- If not found, returns -1
  
  #Dont forget min and max
  max(x) for largest
  min(x) for smallest
  
  #Count occurrences of item in list
  [a,b,c,d,e].count(item)
  #Count occurrences of list 1 items in list 2
  value =  len([i for i in list2 if i in list1 ])
  
  #put anything in square brackets to search list index
  a[0]
  #reverse list of ints by converting to string and list reversing
  str(num)[::-1]
  
  #Strange list rotation
  def rotate_left3(nums):
    a = nums[0]
    nums[0] = nums[1]
    nums[1] = nums[2]
    nums[2] = a
    return nums -> [1,2,3] = [2,3,1]
  
  #Evaluator positioning
  if someting:
  	return (item 1 >= 10)
  else:
  	return (item > 1 and item <= 5)
  
  #One line conditionals
  	#get item index from lst, not there, return -1
  return lst.index(item) if item in lst else -1
  
  #Use F strings
  x = "hello"
  w = "world"
  print(f"{x} {w}")
  
  #Use Swapcase to flip lowercase and uppercase
  string.swapcase()
  
  #List comprehensions
  	#Reverse all words >= 5 letters and print out the modified sentence
  	[word[::-1] if len(word) >= 5 else word for word in words]
  	#Create a dictionary of letters and their frequency of occurrence in a string
  	{i : message.count(i) for i in set(message)}
  	#List all indexes of a specified value
  	def get_indicies(lst, el):
  	[i for i in range(len(lst)) if lst[i] == el]
  	#Edabit solution for odd occurrence of item in list
  	[i for i in lst if lst.count(i) % 2 > 0]
  	#Only return the integers in a list
  	[x for x in l if type(x) == int]
  	#Flatten list of lists
  	flat_list = [item for subitem in lists for item in subitem]
  	#Split int into list of digits
  	split_number = [int(d) for d in str(n)]
  
  #Collapse multiple inputs into one
  	#from this
  	def predict_age(age_1, age_2, age_3, age_4, age_5, age_6, age_7, age_8):
  	#to this
  	def predict_age(*ages)
  
  #Remove char
  def remove_exclamation_marks(s):
      return s.replace('!', '')
  
  #remove duplicate words
  def remove_duplicate_words(s):
      return ' '.join(sorted(set(s.split()), key = s.index))
  
  #Quick Lambda implementation on multiple args - with f"string"
  def newvibe(a,b,c):
  	var1 = lambda x: (x * 5)
  	print(f"This is a: {var1(a)}, This is b: {var1(b)}, This is c: {var1(c)}")
  
new_contents: #Python reminders
  
  # Collapse the list for output
  ''.join(list)
  
  #Flatten list of lists
  flat_list = [item for subitem in lists for item in subitem]
  
  #Exammple for checking list for single digit (string)
  def checker(string):
  	print("Boom!" if "7" in str(string) else "there is no 7 in the list")
  checker([2, 55, 60, 97, 86, 3, 4, 6, 6])
  
  #Scan list for longest string and print max item
  print(max(len(i) for i in string.split()))
  
  #search for highest index of substring
  string.rindex(substring) -- If not found, raises exception
  string.rfind(substring) -- If not found, returns -1
  
  #Dont forget min and max
  max(x) for largest
  min(x) for smallest
  
  #Count occurrences of item in list
  [a,b,c,d,e].count(item)
  #Count occurrences of list 1 items in list 2
  value =  len([i for i in list2 if i in list1 ])
  
  #put anything in square brackets to search list index
  a[0]
  #reverse list of ints by converting to string and list reversing
  str(num)[::-1]
  
  #Strange list rotation
  def rotate_left3(nums):
    a = nums[0]
    nums[0] = nums[1]
    nums[1] = nums[2]
    nums[2] = a
    return nums -> [1,2,3] = [2,3,1]
  
  #Evaluator positioning
  if someting:
  	return (item 1 >= 10)
  else:
  	return (item > 1 and item <= 5)
  
  #One line conditionals
  	#get item index from lst, not there, return -1
  return lst.index(item) if item in lst else -1
  
  #Use F strings
  x = "hello"
  w = "world"
  print(f"{x} {w}")
  
  #Use Swapcase to flip lowercase and uppercase
  string.swapcase()
  
  #List comprehensions
  	#Reverse all words >= 5 letters and print out the modified sentence
  	[word[::-1] if len(word) >= 5 else word for word in words]
  	#Create a dictionary of letters and their frequency of occurrence in a string
  	{i : message.count(i) for i in set(message)}
  	#List all indexes of a specified value
  	def get_indicies(lst, el):
  	[i for i in range(len(lst)) if lst[i] == el]
  	#Edabit solution for odd occurrence of item in list
  	[i for i in lst if lst.count(i) % 2 > 0]
  	#Only return the integers in a list
  	[x for x in l if type(x) == int]
  	#Flatten list of lists
  	flat_list = [item for subitem in lists for item in subitem]
  	#Split int into list of digits
  	split_number = [int(d) for d in str(n)]
  	#Dictionary values for item
  	value = [str(dictionary[i]) for i in string]
  
  #Collapse multiple inputs into one
  	#from this
  	def predict_age(age_1, age_2, age_3, age_4, age_5, age_6, age_7, age_8):
  	#to this
  	def predict_age(*ages)
  
  #Remove char
  def remove_exclamation_marks(s):
      return s.replace('!', '')
  
  #remove duplicate words
  def remove_duplicate_words(s):
      return ' '.join(sorted(set(s.split()), key = s.index))
  
  #Quick Lambda implementation on multiple args - with f"string"
  def newvibe(a,b,c):
  	var1 = lambda x: (x * 5)
  	print(f"This is a: {var1(a)}, This is b: {var1(b)}, This is c: {var1(c)}")
  
subject: Update REMINDERS.py