old_contents: # Copyright (c) 2015, Frappe Technologies Pvt. Ltd. and Contributors
  # MIT License. See license.txt
  from __future__ import unicode_literals
  
  import frappe
  
  import openpyxl
  import re
  from openpyxl.styles import Font
  from openpyxl import load_workbook
  from six import BytesIO, string_types
  
  ILLEGAL_CHARACTERS_RE = re.compile(r'[\000-\010]|[\013-\014]|[\016-\037]')
  # return xlsx file object
  def make_xlsx(data, sheet_name, wb=None):
  
  	if wb is None:
  		wb = openpyxl.Workbook(write_only=True)
  
  	ws = wb.create_sheet(sheet_name, 0)
  
  	row1 = ws.row_dimensions[1]
  	row1.font = Font(name='Calibri',bold=True)
  
  	for row in data:
  		clean_row = []
  		for item in row:
  			if isinstance(item, string_types) and (sheet_name not in ['Data Import Template', 'Data Export']):
  				value = handle_html(item)
  			else:
  				value = item
  
  			if isinstance(item, string_types) and next(ILLEGAL_CHARACTERS_RE.finditer(value), None):
  				# Remove illegal characters from the string
  				value = re.sub(ILLEGAL_CHARACTERS_RE, '', value)
  
  			clean_row.append(value)
  
  		ws.append(clean_row)
  
  	xlsx_file = BytesIO()
  	wb.save(xlsx_file)
  	return xlsx_file
  
  
  def handle_html(data):
  	# return if no html tags found
  	data = frappe.as_unicode(data)
  
  	if '<' not in data:
  		return data
  	if '>' not in data:
  		return data
  
  	from html2text import HTML2Text
  
  	h = HTML2Text()
  	h.unicode_snob = True
  	h = h.unescape(data or "")
  
  	obj = HTML2Text()
  	obj.ignore_links = True
  	obj.body_width = 0
  
  	try:
  		value = obj.handle(h)
  	except Exception:
  		# unable to parse html, send it raw
  		return value
  
  	value = ", ".join(value.split('  \n'))
  	value = " ".join(value.split('\n'))
  	value = ", ".join(value.split('# '))
  
  	return value
  
  def read_xlsx_file_from_attached_file(file_url=None, fcontent=None, filepath=None):
  	if file_url:
  		_file = frappe.get_doc("File", {"file_url": file_url})
  		filename = _file.get_full_path()
  	elif fcontent:
  		from io import BytesIO
  		filename = BytesIO(fcontent)
  	elif filepath:
  		filename = filepath
  	else:
  		return
  
  	rows = []
  	wb1 = load_workbook(filename=filename, read_only=True, data_only=True)
  	ws1 = wb1.active
  	for row in ws1.iter_rows():
  		tmp_list = []
  		for cell in row:
  			tmp_list.append(cell.value)
  		rows.append(tmp_list)
  	return rows
  
new_contents: # Copyright (c) 2015, Frappe Technologies Pvt. Ltd. and Contributors
  # MIT License. See license.txt
  from __future__ import unicode_literals
  
  import frappe
  
  import openpyxl
  import re
  from openpyxl.styles import Font
  from openpyxl import load_workbook
  from six import BytesIO, string_types
  
  ILLEGAL_CHARACTERS_RE = re.compile(r'[\000-\010]|[\013-\014]|[\016-\037]')
  # return xlsx file object
  def make_xlsx(data, sheet_name, wb=None):
  
  	if wb is None:
  		wb = openpyxl.Workbook(write_only=True)
  
  	ws = wb.create_sheet(sheet_name, 0)
  
  	row1 = ws.row_dimensions[1]
  	row1.font = Font(name='Calibri',bold=True)
  
  	for row in data:
  		clean_row = []
  		for item in row:
  			if isinstance(item, string_types) and (sheet_name not in ['Data Import Template', 'Data Export']):
  				value = handle_html(item)
  			else:
  				value = item
  
  			if isinstance(item, string_types) and next(ILLEGAL_CHARACTERS_RE.finditer(value), None):
  				# Remove illegal characters from the string
  				value = re.sub(ILLEGAL_CHARACTERS_RE, '', value)
  
  			clean_row.append(value)
  
  		ws.append(clean_row)
  
  	xlsx_file = BytesIO()
  	wb.save(xlsx_file)
  	return xlsx_file
  
  
  def handle_html(data):
  	# return if no html tags found
  	data = frappe.as_unicode(data)
  
  	if '<' not in data:
  		return data
  	if '>' not in data:
  		return data
  
  	from html2text import HTML2Text
  
  	h = HTML2Text()
  	h.unicode_snob = True
  	h = h.unescape(data or "")
  
  	obj = HTML2Text()
  	obj.ignore_links = True
  	obj.body_width = 0
  
  	try:
  		value = obj.handle(h)
  	except Exception:
  		# unable to parse html, send it raw
  		return data
  
  	value = ", ".join(value.split('  \n'))
  	value = " ".join(value.split('\n'))
  	value = ", ".join(value.split('# '))
  
  	return value
  
  def read_xlsx_file_from_attached_file(file_url=None, fcontent=None, filepath=None):
  	if file_url:
  		_file = frappe.get_doc("File", {"file_url": file_url})
  		filename = _file.get_full_path()
  	elif fcontent:
  		from io import BytesIO
  		filename = BytesIO(fcontent)
  	elif filepath:
  		filename = filepath
  	else:
  		return
  
  	rows = []
  	wb1 = load_workbook(filename=filename, read_only=True, data_only=True)
  	ws1 = wb1.active
  	for row in ws1.iter_rows():
  		tmp_list = []
  		for cell in row:
  			tmp_list.append(cell.value)
  		rows.append(tmp_list)
  	return rows
  
subject: Fix for handle failed html parse