"""
You are given an integer array nums and an array queries where queries[i] = [vali, indexi].
For each query i, first, apply nums[indexi] = nums[indexi] + vali, then print the sum of the even values of nums.
Return an integer array answer where answer[i] is the answer to the ith query.

Example 1:
Input: nums = [1,2,3,4], queries = [[1,0],[-3,1],[-4,0],[2,3]]
Output: [8,6,2,4]
Explanation: At the beginning, the array is [1,2,3,4].
After adding 1 to nums[0], the array is [2,2,3,4], and the sum of even values is 2 + 2 + 4 = 8.
After adding -3 to nums[1], the array is [2,-1,3,4], and the sum of even values is 2 + 4 = 6.
After adding -4 to nums[0], the array is [-2,-1,3,4], and the sum of even values is -2 + 4 = 2.
After adding 2 to nums[3], the array is [-2,-1,3,6], and the sum of even values is -2 + 6 = 4.

Example 2:
Input: nums = [1], queries = [[4,0]]
Output: [0]

Constraints:
1 <= nums.length <= 104
-104 <= nums[i] <= 104
1 <= queries.length <= 104
-104 <= vali <= 104
0 <= indexi < nums.length
"""
from typing import List


class SumOfEvenNumbersAfterQueries:
    def sumEvenAfterQueries(self, nums: List[int], queries: List[List[int]]) -> List[int]:
        even_sum = sum(n for n in nums if n % 2 == 0)
        res = []
        for val, i in queries:
            if nums[i] % 2 == 0:
                even_sum -= nums[i]
            nums[i] += val
            if nums[i] % 2 == 0:
                even_sum += nums[i]
            res.append(even_sum)
        return res
