import unittest

import game_of_chess


class TestPart1(unittest.TestCase):
    """
    --- Day 5: How About a Nice Game of Chess? ---

    You are faced with a security door designed by Easter Bunny engineers
    that seem to have acquired most of their security knowledge by watching
    hacking movies.

    The eight-character password for the door is generated one character at a
    time by finding the MD5 hash of some Door ID (your puzzle input) and an
    increasing integer index (starting with 0).

    A hash indicates the next character in the password if its hexadecimal
    representation starts with five zeroes. If it does, the sixth character
    in the hash is the next character of the password.

    For example, if the Door ID is abc:

    - The first index which produces a hash that starts with five zeroes is
      3231929, which we find by hashing abc3231929; the sixth character of
      the hash, and thus the first character of the password, is 1.
    - 5017308 produces the next interesting hash, which starts with
      000008f82..., so the second character of the password is 8.
    - The third time a hash starts with five zeroes is for abc5278568,
      discovering the character f.

    In this example, after continuing this search a total of eight times, the
    password is 18f47a30.

    Given the actual Door ID, what is the password?
    """

    @unittest.skip('Very long test')
    def test_password(self):
        password = game_of_chess.first_algorithm('abc')
        self.assertEqual('18f47a30', password)
        self.assertEqual(8, len(password))

    @unittest.skip('Very long test')
    def test_puzzle_input(self):
        password = game_of_chess.first_algorithm('abbhdwsy')
        self.assertEqual('801b56a7', password)


class TestPart2(unittest.TestCase):
    """
    --- Part Two ---

    As the door slides open, you are presented with a second door that uses a
    slightly more inspired security mechanism. Clearly unimpressed by the
    last version (in what movie is the password decrypted in order?!), the
    Easter Bunny engineers have worked out a better solution.

    Instead of simply filling in the password from left to right, the hash
    now also indicates the position within the password to fill. You still
    look for hashes that begin with five zeroes; however, now, the sixth
    character represents the position (0-7), and the seventh character is the
    character to put in that position.

    A hash result of 000001f means that f is the second character in the
    password. Use only the first result for each position, and ignore invalid
    positions.

    For example, if the Door ID is abc:

    - The first interesting hash is from abc3231929, which produces
      0000015...; so, 5 goes in position 1: _5______.
    - In the previous method, 5017308 produced an interesting hash;
      however, it is ignored, because it specifies an invalid position (8).
    - The second interesting hash is at index 5357525, which produces
      000004e...; so, e goes in position 4: _5__e___.

    You almost choke on your popcorn as the final character falls into place,
    producing the password 05ace8e3.

    Given the actual Door ID and this new method, what is the password? Be
    extra proud of your solution if it uses a cinematic "decrypting"
    animation.
    """

    @unittest.skip('Very long test')
    def test_password(self):
        password = game_of_chess.second_algorithm('abc')
        self.assertEqual('05ace8e3', password)

    @unittest.skip('Very long test')
    def test_puzzle_input(self):
        password = game_of_chess.second_algorithm('abbhdwsy')
        self.assertEqual('424a0197', password)

