# Given a string and a non-negative int n, we'll say that the front of the string is the first 3 chars, or whatever is there if the string is less than length 3. Return n copies of the front;
#
# front_times('Chocolate', 2) → 'ChoCho'
# front_times('Chocolate', 3) → 'ChoChoCho'
# front_times('Abc', 3) → 'AbcAbcAbc'

def front_times(str, n):
    for i in range(n):
     if len(str) == 3:
        print(str * n, end="")
     elif len(str) < 3:
         print(str * n, end="")
     elif len(str) > 3:
         print(str[:4] * n, end="")


pop = front_times("abc", 3 )