
dic=[

    {"first": "1"},

    {"second": "2"},

    {"third": "1"},

    {"four": "5"},

    {"five": "5"},

    {"six": "9"},

    {"seven": "7"}

]
i=0
b=[]
while i <len(dic):
    for j in dic[i]:
        if dic[i][j] not in b:
            b.append(dic[i][j])
        i=i+1
print(b)

 
    






