
# 简单
"""
给定两个字符串 s 和 t ，编写一个函数来判断 t 是否是 s 的字母异位词。
示例 1:
输入: s = "anagram", t = "nagaram"
输出: true
"""

class Solution(object):
    def isAnagram(self, s, t):
        """
        :type s: str
        :type t: str
        :rtype: bool
        """

        my_dict = {"a":0,"b":0,"c":0,"d":0,"e":0,"f":0,"g":0,"h":0,"i":0,"j":0,"k":0,"l":0,"m":0,
                   "n":0,"o":0,"p":0,"q":0,"r":0,"s":0,"t":0,"u":0,"v":0,"w":0,"x":0,"y":0,"z":0}

        for i in s:
            my_dict[i] += 1

        for i in t:
            my_dict[i] -= 1
        for i in my_dict.values():
            if i != 0:
                return False
        return True




