"""

Given a number N, return true if and only if it is a confusing number, which satisfies the following condition:

We can rotate digits by 180 degrees to form new digits. When 0, 1, 6, 8, 9 are rotated 180 degrees, they become 0, 1, 9, 8, 6 respectively. When 2, 3, 4, 5 and 7 are rotated 180 degrees, they become invalid. A confusing number is a number that when rotated 180 degrees becomes a different number with each digit valid.

 

Example 1:



Input: 6
Output: true
Explanation: 
We get 9 after rotating 6, 9 is a valid number and 9!=6.
Example 2:



Input: 89
Output: true
Explanation: 
We get 68 after rotating 89, 86 is a valid number and 86!=89.
Example 3:



Input: 11
Output: false
Explanation: 
We get 11 after rotating 11, 11 is a valid number but the value remains the same, thus 11 is not a confusing number.
Example 4:



Input: 25
Output: false
Explanation: 
We get an invalid number after rotating 25.
 

Note:

0 <= N <= 10^9
After the rotation we can ignore leading zeros, for example if after rotation we have 0008 then this number is considered as just 8.


"""

	def confusingNumber(self, N):
        S = str(N)
        rotation = {"0" : "0", "1" : "1", "6" : "9", "8" : "8", "9" : "6"}
        result = []
        
        for c in S[::-1]:           # iterate in reverse
            if c not in rotation:
                return False
            result.append(rotation[c])
                
        return "".join(result) != S
      
      """
      Convert N to a string.
      Map each digit of N to its rotation, returning False if no rotation.
      Compare the reversed mapping to the original string.
      """
