#--------Problem 1 Project Euler--------#
#---------Multiples of 3 and 5----------#
"""
If we list all the natural numbers below 10 that are multiples of 3 or 5, we get 3, 5, 6 and 9. The sum of these multiples is 23.

Find the sum of all the multiples of 3 or 5 below 1000.
"""
#way I tried
def multiples(num):
    numlist = []
    for x in range(num):
        if x % 3 == 0:
            numlist.append(x)
        elif x % 5 == 0:
            numlist.append(x)
    return sum(numlist[1:])

print(multiples(1000))
