"""
The sum of the squares of the first ten natural numbers is,

12 + 22 + ... + 102 = 385
The square of the sum of the first ten natural numbers is,

(1 + 2 + ... + 10)2 = 552 = 3025
Hence the difference between the sum of the squares of the
first ten natural numbers and the square of the sum is 3025 − 385 = 2640.

Find the difference between the sum of the squares of the
first one hundred natural numbers and the square of the sum.
"""

class Solution:

    def diffSquare(self, n):
        sumOfSquare = (((2*n)+1)*(n+1)*(n))//6
        squareOfSum = ((n*(n+1))//2)**2
        return squareOfSum - sumOfSquare

s = Solution()
print(s.diffSquare(100))
