#Given a non-negative integer num, repeatedly add all its digits until the result has only one digit.

#For example:
#Given num = 38, the process is like: 3 + 8 = 11, 1 + 1 = 2. Since 2 has only one digit, return it.


def addDigits(self, num):
    while(num/10!=0):
        num = num/10 + num%10
    return num
    
