#number and boolen
n1 = 900
print (n1)
n2 = type(n1) #Kieu cua bien
print (n2)
n3 = 100000000000000000000000
print (n3)
s = 2 ** 2 # so mu
print(s)
s = s+1
print (s)
s1 = 5 * s
print (s)
f = 9.5
type(f) 
c1 = 80
c2 = 115.5
c = c1 + c2
print(type(c),id(c))
print(c)
a = 10
b = 5
tong = a + b
print(tong)
hieu = a - b
print(hieu)
thuong = a / b
print(thuong) #So nay dang fload
laydu = 10 % 3
print(laydu)
mi = min(3,1,2,5)
print(mi) #in ra số nho nhat
ma = max(3,4,9,6)
print(ma) #in ra sô lớn nhất
abs(-115)# lấy trị tuyệt đối
