"""\
    4. Second Index
       
       You are given two strings and you have to find an index of the second
       occurrence of the second string in the first one.

       Let's go through the first example where you need to find the second
       occurrence of "s" in a word "sims". It’s easy to find its first occurrence
       with a function index or find which will point out that "s" is the first
       symbol in a word "sims" and therefore the index of the first occurrence is
       0. But we have to find the second "s" which is 4th in a row and that means
       that the index of the second occurrence (and the answer to a question)
       is 3.

       Input: Two strings.

       Output: Int or None

       Example:

        second_index("sims", "s") == 3
        second_index("find the river", "e") == 12
        second_index("hi", " ") is None
"""

def second_index(text: str, symbol: str):
    """
        returns the second index of a symbol in a given text
    """

    j = []

    for i in range(0, len(text)):
        if text[i] == symbol:
            j.append(symbol)
        if len(j) == 2:
            break

    if len(j) > 1:
        return i
    
#Example:
print(second_index("sims", "s"))
print(second_index("find the river", "e"))
print(second_index("hi", " "))
print(second_index("hi mayor", " "))
print(second_index("eee", "e"))

# Ez is működik. :)
