# -*- coding: utf-8 -*-
class Solution:
    def isMatch(self, s: str, p: str) -> bool:
        pass



    '''
        返回处理后的pattern
    '''
    def neatPattern(self, p:str):
        pass


a=[[1],[11,22],[111,222,333]]

b=[[2],[33,44]]

c=[33,44]
d=[44, 33]

c.reverse()
print(c == d)