# -*- coding:utf-8 -*-
"""
Using names.txt (right click and 'Save Link/Target As...'), a 46K text file containing over 
five-thousand first names, begin by sorting it into alphabetical order. Then working out the 
alphabetical value for each name, multiply this value by its alphabetical position in the 
list to obtain a name score.

For example, when the list is sorted into alphabetical order, COLIN, 
which is worth 3 + 15 + 12 + 9 + 14 = 53, is the 938th name in the list. So, COLIN would 
obtain a score of 938 Ă 53 = 49714.

What is the total of all the name scores in the file?

"""
lookup_table = {'A':1,'B':2,'C':3,'D':4,'E':5,'F':6,'G':7,
				'H':8,'I':9,'J':10,'K':11,'L':12,'M':13,'N':14,
				'O':15,'P':16,'Q':17,'R':18,'S':19,'T':20,'U':21,
				'V':22,'W':23,'X':24,'Y':25,'Z':26}

def get_string_scores(string):
	scores = 0
	for i,ch in enumerate(string):
		scores += lookup_table[ch]
	return scores

def get_total_scores(filename):
	name_file = open(filename,"r+")
	name_file.seek(0,2)
	file_size = name_file.tell()
	name_file.seek(0,0)
	file_content = name_file.read(file_size)
	name_list = file_content.replace("\"","").split(',')
	name_list.sort()
	scores = 0
	rank = 1
	for name in name_list:
		scores += (get_string_scores(name) * rank)
		rank += 1
	return scores

if __name__ == "__main__":
	print get_total_scores("name.txt")
# Answer:871198282
