"""
编写一个函数，其作用是将输入的字符串反转过来。输入字符串以字符数组 char[] 的形式给出。
不要给另外的数组分配额外的空间，你必须原地修改输入数组、使用 O(1) 的额外空间解决这一问题。
你可以假设数组中的所有字符都是 ASCII 码表中的可打印字符。

 
示例 1：
输入：["h","e","l","l","o"]
输出：["o","l","l","e","h"]

示例 2：
输入：["H","a","n","n","a","h"]
输出：["h","a","n","n","a","H"]

来源：力扣（LeetCode）
链接：https://leetcode-cn.com/problems/reverse-string
"""
from typing import List
class Solution:
    def reverseString(self, s: List[str]) -> None:
        """
        Do not return anything, modify s in-place instead.
        """
        size = len(s)
        if size == 0:
            return s
        l = 0
        r = size - 1
        while l < r:
            s[l],s[r] = s[r],s[l]
            l += 1
            r -= 1
        return s

s = ["h","e","l","l","o"]
print(Solution().reverseString(s))