# I always thought that my old friend John was rather richer than he looked, but I never knew exactly how much money
# he actually had. One day (as I was plying him with questions) he said:
#
# "Imagine I have between m and n Zloty..." (or did he say Quetzal? I can't remember!)
# "If I were to buy 9 cars costing c each, I'd only have 1 Zloty (or was it Meticals?) left."
# "And if I were to buy 7 boats at b each, I'd only have 2 Ringglets (or was it Zloty?) left."
# Could you tell me in each possible case:
#
# how much money f he could possibly have ? the cost c of a car? the cost b of a boat? So, I will have a better idea
# about his fortune. Note that if m-n is big enough, you might have a lot of possible answers.
#
# Each answer should be given as ["M: f", "B: b", "C: c"] and all the answers as [ ["M: f", "B: b", "C: c"],
# ... ]. "M" stands for money, "B" for boats, "C" for cars.
#
# Note: m, n, f, b, c are positive integers, where 0 <= m <= n or m >= n >= 0. m and n are inclusive.
#
# Examples:
# howmuch(1, 100)      => [["M: 37", "B: 5", "C: 4"], ["M: 100", "B: 14", "C: 11"]]
# howmuch(1000, 1100)  => [["M: 1045", "B: 149", "C: 116"]]
# howmuch(10000, 9950) => [["M: 9991", "B: 1427", "C: 1110"]]
# howmuch(0, 200)      => [["M: 37", "B: 5", "C: 4"], ["M: 100", "B: 14", "C: 11"], ["M: 163", "B: 23", "C: 18"]]
# Explanation of the results for howmuch(1, 100):
#
# In the first answer his possible fortune is 37:
# so he can buy 7 boats each worth 5: 37 - 7 * 5 = 2
# or he can buy 9 cars worth 4 each: 37 - 9 * 4 = 1
# The second possible answer is 100:
# he can buy 7 boats each worth 14: 100 - 7 * 14 = 2
# or he can buy 9 cars worth 11: 100 - 9 * 11 = 1


def how_much(m, n):
    f_min = min(m, n)
    f_max = max(m, n)
    result = []

    for i in range(f_min, f_max + 1):
        if i % 7 == 2 and i % 9 == 1:
            result.append(["M: " + str(i), "B: " + str(i // 7), "C: " + str(i // 9)])

    return result
