def lcm(x, y):
    #获取最大的数

    if x >y:
        greater = x
    else:
        greater = y
    
    while(True):
        if(greater%x==0) and (greater%y==0):
            lcm=greater
            break
        greater += 1
    return lcm

#获取用户输入
num1 = int(input("请输入第一个数字："))
num2 = int(input("请输入第二个数字："))

print(num1,"和",num2,"的最小公倍数是",lcm(num1,num2))