#The sum of the squares of the first ten natural numbers is,

#12 + 22 + ... + 102 = 385
#The square of the sum of the first ten natural numbers is,

#(1 + 2 + ... + 10)2 = 552 = 3025
#Hence the difference between the sum of the squares of the first ten natural numbers and the square of the sum is 3025 − 385 = 2640.

#Find the difference between the sum of the squares of the first one hundred natural numbers and the square of the sum.


n=100


sum_square=((n*(n+1))/2)**2

squares_sum=(n*(n+1)*(2*n+1))/6

ans=sum_square-squares_sum

print(ans)


#Answer : 25164150
