def odd_count(lst):
    """Given a list of lists of strings, where each string is a representation
    of an array of digits, return a list.
    Each element i of the output should be "the number of odd elements in the
    string i of the input." where all the i's should be replaced by the number
    of odd digits in the i'th string of the input.

    >>> odd_count(['1234567'])
    ["the number of odd elements 4n the str4ng 4 of the 4nput."]
    >>> odd_count(['3',"11111111"])
    ["the number of odd elements 1n the str1ng 1 of the 1nput.",
     "the number of odd elements 8n the str8ng 8 of the 8nput."]
     
    Example solution:
    # line 1
    res = []
    # line 2
    for arr in lst:
        # line 3
        n = sum(int(d)%2==1 for d in arr)
        # line 4
        res.append("the number of odd element " + str(n) + "n the str"+ str(n) +"ing "+ str(n) +" of the "+ str(n) +"input.")
    # line 5
    return res
    
    """
    # Please print out which line of the above program contains an error. E.g. if the bug is on line 4 then print 4
    # END OF CONTEXT
    print("4")
    # END OF SOLUTION

def check(candidate):

    import io
    from contextlib import redirect_stdout

    f = io.StringIO()
    with redirect_stdout(f):
        candidate([])
    out = f.getvalue().strip('\n')

    assert "4" == out
    for i in range(0, 10):
        if i != 4:
            assert str(i) != out

if __name__ == '__main__':
    check(odd_count)
