from math import pow, ceil

# # Sum square difference
# The sum of the squares of the first ten natural numbers is,
# 12 + 22 + ... + 102 = 385
# The square of the sum of the first ten natural numbers is,
# (1 + 2 + ... + 10)2 = 552 = 3025
# Hence the difference between the sum of the squares of the
# first ten natural numbers and the square of the sum is 3025 − 385 = 2640.
# Find the difference between the sum of the squares of the
# first one hundred natural numbers and the square of the sum.

def solution6(max):
    sumOfSquares = ceil(sum([pow(x, 2) for x in range(1, max+1)]))
    squareOfSum = ceil(pow(sum([x for x in range(1, max + 1)]), 2))

    return squareOfSum - sumOfSquares


print(solution6(100))
