"""
1464. Maximum Product of Two Elements in an Array

Given the array of integers nums, you will choose two different indices i and j of that array. Return the maximum value of (nums[i]-1)*(nums[j]-1).

Example 1:
    Input: nums = [3,4,5,2]
    Output: 12
    Explanation: If you choose the indices i=1 and j=2 (indexed from 0), you will get the maximum value, that is, (nums[1]-1)*(nums[2]-1) = (4-1)*(5-1) = 3*4 = 12.

Example 2:
    Input: nums = [1,5,4,5]
    Output: 16
    Explanation: Choosing the indices i=1 and j=3 (indexed from 0), you will get the maximum value of (5-1)*(5-1) = 16.

Example 3:
    Input: nums = [3,7]
    Output: 12

Constraints:
    2 <= nums.length <= 500
    1 <= nums[i] <= 10^3
"""


class Solution(object):
    def maxProduct(self, nums):
        """
        :type nums: List[int]
        :rtype: int
        """
        nums = sorted(nums)

        return (nums.pop() - 1) * (nums.pop() - 1)


if __name__ == '__main__':
    print(Solution().maxProduct([1, 5, 4, 5]))

