






























            dict[i]+=1
            dict[i]=1
            dict[i]=1
        elif(i in dict):
        else:
        if(len(dict)==0):
        result = has_palindrome_permutation('')
        result = has_palindrome_permutation('a')
        result = has_palindrome_permutation('aabbcd')
        result = has_palindrome_permutation('aabcbcd')
        result = has_palindrome_permutation('aabccbdd')
        result = has_palindrome_permutation('aabcd')
        return False
        return True
        return True
        self.assertFalse(result)
        self.assertFalse(result)
        self.assertTrue(result)
        self.assertTrue(result)
        self.assertTrue(result)
        self.assertTrue(result)
    # Check if any permutation of the input is a palindrome
    '=]']
    def test_empty_string(self):
    def test_no_permutation_with_even_number_of_chars(self):
    def test_no_permutation_with_odd_number_of_chars(self):
    def test_one_character_string(self):
    def test_permutation_with_even_number_of_chars(self):
    def test_permutation_with_odd_number_of_chars(self):
    dict={}
    elif(len(the_string)%2==0 and len(dict)<=(len(the_string)//2)):
    else:
    for i in the_string:
    if(len(dict)<=(len(the_string)//2)+1 and len(the_string)%2!=0):
# Tests
class Test(unittest.TestCase):
def has_palindrome_permutation(the_string):
import unittest
unittest.main(verbosity=2LAJDLKFLKJHHHHHHHHHHHHHHHHHH9-=-]['07-[7\