# Multiples of 3 and 5

# Problem 1
# If we list all the natural numbers below 10 that are multiples of 3 or 5, we get 3, 5, 6 and 9. The sum of these multiples is 23.

# Find the sum of all the multiples of 3 or 5 below 1000.
import time

start_time = time.time()
sum = 0
for i in range(1, 1000):
    if i % 3 == 0 or i % 5 == 0:
        sum += i

print(sum)
seconds = time.time() - start_time
print('Time Taken:', time.strftime("%H:%M:%S", time.gmtime(seconds)))
print("--- %s seconds ---" % (time.time() - start_time))
