''' FIND 33:
Given a list of ints,return true if the array contains a 3 next to a 3 somewhere.'''
def has_33(nums):
	for i in range(0,len(nums)-1):
		if nums[i]==3 and nums[i+1]==3:
			return True
	return False

print(has_33([1,3,3]))
print(has_33([1,3,1,3]))
print(has_33([3,3,3]))
