# python program to check if x is a perfect square
import math

# A utility function that returns true if x is perfect square
def isPerfectSquare(x):
	s = int(math.sqrt(x))
	return s*s == x

# Returns true if n is a Fibinacci Number, else false
def isFibonacci(n):

	# n is Fibinacci if one of 5*n*n + 4 or 5*n*n - 4 or both
	# is a perferct square
	return isPerfectSquare(5*n*n + 4) or isPerfectSquare(5*n*n - 4)

 
for i in range(1,11):
	if (isFibonacci(i) == True):
		print i,"is a Fibonacci Number"
	else:
		print i,"is a not Fibonacci Number "
