# Question 9 - Finding the percentage:
# The provided code stub will read in a dictionary containing key/value pairs of name:[marks] for a list of students.
# Print the average of the marks array for the student name provided, showing 2 places after the decimal.
#
# Example
# marks key:value pairs are
# 'alpha':[20,30,40]
# 'beta':[30,50,70]
# query_name = 'beta'
# The query_name is 'beta'. beta's average score is .(30+50+70)/3 = 50.0.
#
# Input Format
#
# The first line contains the integer n, the number of students' records.
# The next n lines contain the names and marks obtained by a student, each value separated by a space.
# The final line contains query_name, the name of a student to query.
#
# Constraints
#
# 2<=n<=10
# 0 <= marks[i] <= 100
# length of the marks array = 3
#
# Output Format
#
# Print one line: The average of the marks obtained by the particular student correct to 2 decimal places.
#
# Sample Input 0
#
# 3
# Krishna 67 68 69
# Arjun 70 98 63
# Malika 52 56 60
# Malika
#
#
# Sample Output
#
# 56.00
#
# Explanation 0
#
# Marks for Malika {52,56,60} are whose average is (56+52+60)/3 = 56
#
# Sample Input 1
#
# 2
# Harsh 25 26.5 28
# Anurag 26 28 30
# Harsh
#
# Sample Output 1
#
# 26.50

students_grade = {"Harsh": [25,26.5,28],"Anurag": [26,28,30],"Krishna":[67,68,69],"Arjun":[70,98,63],
                  "Malika":[52,56,60]}
query_name = input("Enter student name to find average marks: ")
if query_name in students_grade:
    query_name = students_grade[query_name]
    avg = sum(query_name)/3
    print("{:.2f}".format(avg))
