"""
Given an integer array nums, find the contiguous subarray (containing at least one number) which has the largest sum and return its sum.

A subarray is a contiguous part of an array.

Example 1:
Input: nums = [-2,1,-3,4,-1,2,1,-5,4]
Output: 6
Explanation: [4,-1,2,1] has the largest sum = 6.

Example 2:
Input: nums = [1]
Output: 1

Example 3:
Input: nums = [5,4,-1,7,8]
Output: 23

Constraints:
1 <= nums.length <= 10^5
-10^4 <= nums[i] <= 10^4

Follow up: If you have figured out the O(n) solution, try coding another solution using the divide and conquer approach, which is more subtle.
"""
from typing import List


class MaximumSubarray:
    def maxSubArray(self, nums: List[int]) -> int:
        for i in range(1, len(nums)):
            if nums[i - 1] > 0:
                nums[i] += nums[i - 1]
        return max(nums)
