# If we list all the natural numbers below 10 that are multiples of 3 or 5, we get 3, 5, 6 and 9.
# The sum of these multiples is 23.
# Find the sum of all the multiples of 3 or 5 below 1000.

# Comments Section:
# - Straight forward algorithm.

def problem1():
    sum = 0
    for i in range(1000):
        if ((i%3 == 0) or (i%5 == 0)):
            sum += i
    return sum
    
