# You are choreographing a circus show with various animals. For one act, you are given two kangaroos on a number line ready to jump in the positive direction (i.e, toward positive infinity).

# The first kangaroo starts at location  and moves at a rate of  meters per jump.
# The second kangaroo starts at location  and moves at a rate of  meters per jump.
# You have to figure out a way to get both kangaroos at the same location at the same time as part of the show. If it is possible, return YES, otherwise return NO.

# For example, kangaroo  starts at  with a jump distance  and kangaroo  starts at  with a jump distance of . After one jump, they are both at , (, ), so our answer is YES.

# Function Description

# Complete the function kangaroo in the editor below. It should return YES if they reach the same position at the same time, or NO if they don't.

# kangaroo has the following parameter(s):

# x1, v1: integers, starting position and jump distance for kangaroo 1
# x2, v2: integers, starting position and jump distance for kangaroo 2
# Input Format

# A single line of four space-separated integers denoting the respective values of , , , and .

# Constraints

# Output Format

# Print YES if they can land on the same location at the same time; otherwise, print NO.

# Note: The two kangaroos must land at the same location after making the same number of jumps.

# Sample Input 0

# 0 3 4 2
# Sample Output 0

# YES
# Explanation 0

# The two kangaroos jump through the following sequence of locations:

# image

# From the image, it is clear that the kangaroos meet at the same location (number  on the number line) after same number of jumps ( jumps), and we print YES.

# Sample Input 1

# 0 2 5 3
# Sample Output 1

# NO
# Explanation 1

# The second kangaroo has a starting location that is ahead (further to the right) of the first kangaroo's starting location (i.e., ). Because the second kangaroo moves at a faster rate (meaning ) and is already ahead of the first kangaroo, the first kangaroo will never be able to catch up. Thus, we print NO.


def kangaroo(x1, v1, x2, v2):

    if x1 < x2:
        jump_diff = v1 - v2
        if jump_diff <= 0:
            return "NO"
        advantange = x2 - x1
        multiple = 1
        while(multiple * jump_diff) < advantange:
            multiple += 1
        if (multiple * jump_diff) == advantange:
            return "YES"
        else:
            return "NO"

    if x2 < x1:
        jump_diff = v2 - v1
        if jump_diff <= 0:
            return "NO"
        advantange = x1 - x2
        multiple = 1
        while(multiple * jump_diff) < advantange:
            multiple += 1
        if (multiple * jump_diff) == advantange:
            return "YES"
        else:
            return "NO"


s = list(map(int, "4602 8519 7585 8362".split()))
print(kangaroo(s[0], s[1], s[2], s[3]))
