# https://leetcode.com/problems/find-numbers-with-even-number-of-digits/
# 1295. Find Numbers with Even Number of Digits
# Given an array nums of integers, return how many of them contain an even number of digits.
# Example 1:
# Input: nums = [12,345,2,6,7896]
# Output: 2
# Explanation:
# 12 contains 2 digits (even number of digits).
# 345 contains 3 digits (odd number of digits).
# 2 contains 1 digit (odd number of digits).
# 6 contains 1 digit (odd number of digits).
# 7896 contains 4 digits (even number of digits).
# Therefore only 12 and 7896 contain an even number of digits.
# Example 2:
# Input: nums = [555,901,482,1771]
# Output: 1
# Explanation:
# Only 1771 contains an even number of digits.
# Constraints:
#     1 <= nums.length <= 500
#     1 <= nums[i] <= 10^5

def findNumbers(nums):
    count = 0
    for n in nums:
        if len(str(n)) % 2 == 0:
            count += 1
    return count
