#print datetime.timedelta()

# print datetime.date(2007, 12, 5)
# 32513 #birthday
# 43145 #today

# inputs
# soltuion=procedure
# outputs

# Pythonista's guide to all problems in the galaxy
# 0. Don't panic
# 1. what are the INPUT's ?
# 2. what are the OUTPUT's ?
# 3. Solve the problem! examples by hand
# 4. Simple Mechanical Solution (not optimize in begining)


def DaysBetweenDates(year1, month1, day1, year2, month2, day2)


# roughly 100 * 365 ~35,500 days
# computer time to count 100 years in days
# modern processor ~1B instructions per second, 1 ns/instruc
# each day ~1000 instruc
# 36.5M instruc / 1B
# 0.036 seconcs
