cafe = "Octane"
balance = 8.49
#Atlanta is full of great coffee places. Unfortunately, great
#coffee is usually expensive. The variables above will
#contain a balance and a cafe name. Below are the prices of
#a cup of coffee at each of three locations:
#
# - Octane: $6
# - Galloway: $5
# - Starbucks: $4
# - Revelator: $3
# - Dunkin: $2
#
#Add some code above that will print one of the following
#two messages depending on whether the value of balance is
#high enough to buy a cup of coffee at the given cafe.
#
# - If it is sufficient, print "With [balance] dollars, I
#   can buy coffee at [cafe]"
# - If it is not sufficient, print "With [balance] dollars,
#   I cannot buy coffee at [cafe]"


#Add your code here!
if cafe == "Octane":
    if balance >= 6 :
        print("With",balance,"dollars, I can buy coffee at Octane")
    else:
        print("With",balance,"dollars, I cannot buy coffee at Octane")
elif  cafe == "Galloway":
    if balance >= 5:
        print("With",balance,"dollars, I can buy coffee at Galloway")
    else:
        print("With",balance,"dollars, I cannot buy coffee at Galloway")
elif cafe == "Starbucks":
    if balance >= 4:
        print("With",balance,"dollars, I can buy coffee at Starbucks")
    else:
        print("With",balance,"dollars, I cannot buy coffee at Starbucks")
elif cafe == "Revelator":
    if balance >= 3:
        print("With",balance,"dollars, I can buy coffee at Revelator")
    else:
          print("With",balance,"dollars, I cannot buy coffee at Revelator")
elif cafe == "Dunkin":
    if balance >= 2:
        print("With",balance,"dollars, I can buy coffee at Dunkin")
    else:
          print("With",balance,"dollars, I cannot buy coffee at Dunkin")          
