# Write a program, which will find all such numbers
# between 1000 and 3000 (both included) such that each
#  digit of the number is an even number.

# val = []
# for i in range(1000, 3001):
#    s = str(i)
#    if (int(s[0])%2==0) and (int(s[1])%2==0) and
# (int(s[2])%2==0) and (int(s[3])%2==0):
#       val.append(s)
# print ",".join(val)


print ("HEllo World")

# val = [
#    i
#    for i in range(1000, 3001)
#    if all([j % 2 == 0 for j in str(i)])
# ]
