"""
(006)
The sum of the squares of the first ten natural numbers is,

1**2 + 2**2 + ... + 10**2 = 385
The square of the sum of the first ten natural numbers is,

(1 + 2 + ... + 10)**2 = 552 = 3025
Hence the difference between the sum of the squares of the first ten natural numbers and the
square of the sum is 3025 − 385 = 2640.

Find the difference between the sum of the squares of the first one hundred natural numbers
and the square of the sum.
"""
sumSqr = 0
sqrSum = 0
dif = 0

for i in range(1, 101):
    sumSqr = sumSqr + i**2

for i in range(1, 101):
    sqrSum = sqrSum + i
sqrSum = sqrSum ** 2

print(sqrSum - sumSqr)

# TODO: Discuss naming conventions
# sqr_sum: snake case
# sqrSum: camelCase
