"""
1165. single row keyboard
Difficulty: Easy

There is a special keyboard with all keys in a single row.

Given a string keyboard of length 26 indicating the layout of the keyboard (indexed from 0 to 25), initially your finger is at index 0. To type a character, you have to move your finger to the index of the desired character. The time taken to move your finger from index i to index j is |i - j|.

You want to type a string word. Write a function to calculate how much time it takes to type it with one finger.



Example 1:

Input: keyboard = "abcdefghijklmnopqrstuvwxyz", word = "cba"
Output: 4
Explanation: The index moves from 0 to 2 to write 'c' then to 1 to write 'b' then to 0 again to write 'a'.
Total time = 2 + 1 + 1 = 4.


Example 2:

Input: keyboard = "pqrstuvwxyzabcdefghijklmno", word = "leetcode"
Output: 73


Constraints:

keyboard.length == 26
keyboard contains each English lowercase letter exactly once in some order.
1 <= word.length <= 10^4
word[i] is an English lowercase letter.
"""


class Solution:
    def calculateTime(self, keyboard: str, word: str) -> int:

        d = [None] * 26

        for idx, ch in enumerate(keyboard):
            d[ord(ch) - 97] = idx

        result = d[ord(word[0]) - 97]

        for idx, ch in enumerate(word[1:]):
            result += abs(
                d[ord(ch) - 97] - d[ord(word[idx]) - 97]
            )

        return result


if __name__ == "__main__":

    s = Solution()
    s.calculateTime("abcdefghijklmnopqrstuvwxyz", "cba") == 4
