"""
1464. Maximum Product of Two Elements in an Array
Easy
Given the array of integers nums, you will choose two different indices i and j of that array. Return the maximum value of (nums[i]-1)*(nums[j]-1).

 

Example 1:

Input: nums = [3,4,5,2]
Output: 12 
Explanation: If you choose the indices i=1 and j=2 (indexed from 0), you will get the maximum value, that is, (nums[1]-1)*(nums[2]-1) = (4-1)*(5-1) = 3*4 = 12. 

Example 2:

Input: nums = [1,5,4,5]
Output: 16
Explanation: Choosing the indices i=1 and j=3 (indexed from 0), you will get the maximum value of (5-1)*(5-1) = 16.

Example 3:

Input: nums = [3,7]
Output: 12

 

Constraints:

    2 <= nums.length <= 500
    1 <= nums[i] <= 10^3

"""
class Solution:
    def maxProduct(self, nums: List[int]) -> int:
        a=[(e-1) for e in nums]
        tmp=float('-inf')
        ii=-1
        for i,e in enumerate(a):
            if e>tmp:
                tmp=e
                ii=i
        del a[ii]
        return max(a)*tmp

class Solution:
    def maxProduct(self, nums: List[int]) -> int:
        MAX1=MAX2=-math.inf
        for e in nums:
            MAX2=max(MAX2,e)
            if MAX2>MAX1:
                MAX1,MAX2=MAX2,MAX1
        return (MAX1-1)*(MAX2-1)
