






def count(text, ltr):
    count = 0
    for c in text:
        if c == ltr:
                count += 1
    return (count)

print(count("banana", "b"))
return(count("banana", "n") == 2)



def find2(strng, ch=, start=0, end=None):
    ix = start
    if end is None
        end= len(strng)
    while ix < end:
        if strng[ix] == ch:
            return ix
        ix += 1
    return -1

print(find2("banana", "a", 2))
test(find2("banana", "a", 2) == 3)