Python 3.7.4 (tags/v3.7.4:e09359112e, Jul  8 2019, 19:29:22) [MSC v.1916 32 bit (Intel)] on win32
Type "help", "copyright", "credits" or "license()" for more information.
>>> from getpass import getpass
uname=input('enter u name')
pwd=getpass('enter pwd')
if uname=="sai" and pwd=="sai@123":
    print('Welcome',uname)
else:
    print('invalid uname or password')
