"""
973. K Closest Points to Origin
Medium

964

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We have a list of points on the plane.  Find the K closest points to the origin (0, 0).

(Here, the distance between two points on a plane is the Euclidean distance.)

You may return the answer in any order.  The answer is guaranteed to be unique (except for the order that it is in.)



Example 1:

Input: points = [[1,3],[-2,2]], K = 1
Output: [[-2,2]]
Explanation:
The distance between (1, 3) and the origin is sqrt(10).
The distance between (-2, 2) and the origin is sqrt(8).
Since sqrt(8) < sqrt(10), (-2, 2) is closer to the origin.
We only want the closest K = 1 points from the origin, so the answer is just [[-2,2]].
Example 2:

Input: points = [[3,3],[5,-1],[-2,4]], K = 2
Output: [[3,3],[-2,4]]
(The answer [[-2,4],[3,3]] would also be accepted.)


Note:

1 <= K <= points.length <= 10000
-10000 < points[i][0] < 10000
-10000 < points[i][1] < 10000
"""
import math


class Solution:
    def kClosest(self, points, K):
        dis = [[(x, y), math.sqrt(x**2 + y**2)] for x, y in points]
        orderByDis = sorted(dis, key=lambda ele: ele[1])
        return [i[0] for i in orderByDis][:K]


s = Solution()
points, K = [[3, 3], [5, -1], [-2, 4]], 2
test = s.kClosest(points, K)
print(test)
# Output: [[3,3],[-2,4]]
