"""
给定一个Excel表格中的列名称，返回其相应的列序号。

例如，

    A -> 1
    B -> 2
    C -> 3
    ...
    Z -> 26
    AA -> 27
    AB -> 28 
    ...
示例 1:

输入: "A"
输出: 1
示例 2:

输入: "AB"
输出: 28
示例 3:

输入: "ZY"
输出: 701
"""

class Solution(object):
    def titleToNumber(self, s):
        """
        :type s: str
        :rtype: int
        """
        letters = {"A": 1, "B": 2, "C": 3, "D": 4, "E": 5, "F": 6, "G": 7, "H": 8, "I": 9, "J": 10, "K": 11, "L": 12, "M": 13, "N": 14, "O": 15, "P": 16, "Q": 17, "R": 18, "S": 19, "T": 20, "U": 21, "V": 22, "W": 23, "X": 24, "Y": 25, "Z": 26}
        s = s.upper()
        ret = 0
        b = 0
        for c in reversed(s):
          ret += letters[c] * 26 ** (b)
          b += 1
        return ret
