Brian goes fishing twice as often as Chris, but catches 2/5 times fewer fish than Chris per trip. If Brian caught 400 fish every time he went fishing, how many fish did they catch altogether if Chris went fishing 10 times? Let's think step by step and output the final answer after "####".
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If Brian caught 400 fish in one trip, he caught 2*400=<<400*2=800>>800 fish in two trips.
Since Brian catches 2/5 times less fish than Chris per trip, Chris catches 2/5*400=<<2/5*400=160>>160 more fish in one fishing trip.
Chris's total number of fish in one trip is 400+160 = <<400+160=560>>560 fish.
In 10 trips, Chris catches 560*10=<<560*10=5600>>5600 fish.
If in his two trips Brian catches 800 fish, and he goes fishing twice as often as Chris, if Chris goes fishing 10 times, Brian will catch 800*10=<<800*10=8000>>8000 fish.
The total number of fish they'll catch if Chris goes fishing ten times is 8000+5600=<<8000+5600=13600>>13600
#### 13600
Brian goes fishing twice as often as Chris, but catches 2/5 times fewer fish than Chris per trip. If Brian caught 400 fish every time he went fishing, how many fish did they catch altogether if Chris went fishing 10 times?
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