A van is delivering  180 bottles of drinks to a neighborhood, and each bottle contains either cider or beer or a mixture of two. Out of the  180 bottles, 40 contain only cider, 80 contain only beer, and the rest are a mixture of the two drinks. If the delivery man gives half the number of each bottle of drink to the first house, how many bottles does the first house get? Let's think step by step and output the final answer after "####".
user
The total number of bottles containing cider or beer is 40+80 = <<40+80=120>>120
If the number of bottles in the van was 180, then 180-120 =<<180-120=60>>60 contains a mixture of the two drinks.
At the first house, the delivery man dropped 1/2*40 = <<1/2*40=20>>20 bottles.
There were also 1/2*80 = <<1/2*80=40>>40 bottles of beer that the delivery man gave to the first house.
Together, the first house received 40+20 = <<40+20=60>>60 bottles of cider and beer
The total number of bottles that had a mixture of the two drinks that were dropped at the first house is 1/2*60 = <<1/2*60=30>>30
The first house got 60+30 = <<60+30=90>>90 bottles of all types of drinks.
#### 90
A van is delivering  180 bottles of drinks to a neighborhood, and each bottle contains either cider or beer or a mixture of two. Out of the  180 bottles, 40 contain only cider, 80 contain only beer, and the rest are a mixture of the two drinks. If the delivery man gives half the number of each bottle of drink to the first house, how many bottles does the first house get?
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