Vermont opened up 4 web pages on his web browser and found 12 ads on the first web page and twice as many ads on the second web page as the first web page. When he opened the third web page, he found 24 more ads than the number of ads on the second web page. If the fourth web page had 3/4 times as many ads as the second web page, calculate the total number of ads Vermont clicked on if he clicked on 2/3 of them. Let's think step by step and output the final answer after "####".
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If Vermont found 12 ads on the first web page and twice as many ads on the second web page as the first web page, he found 12*2 = <<12*2=24>>24 ads on the second web page.
The first and the second web page had a total of 12+24 =<<12+24=36>>36
Vermont also found 24 more ads on the third web page than the second web page, a total of 24+24 = <<24+24=48>>48 ads.
The first three web pages had 48+36 = <<48+36=84>>84 ads
The fourth web page had 3/4 times as many ads as the second web page, a total of 3/4*24 =<<3/4*24=18>>18 ads
In all the web pages Vermont opened, he found 84+18 = <<84+18=102>>102 ads
If he clicked on 2/3 of them, he clicked on 2/3*102=<<2/3*102=68>>68 ads.
#### 68
Vermont opened up 4 web pages on his web browser and found 12 ads on the first web page and twice as many ads on the second web page as the first web page. When he opened the third web page, he found 24 more ads than the number of ads on the second web page. If the fourth web page had 3/4 times as many ads as the second web page, calculate the total number of ads Vermont clicked on if he clicked on 2/3 of them.
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