Gail has two fish tanks. The first tank is twice the size of the second tank. There are 48 gallons of water in the first tank. She follows the rule of one gallon of water per inch of fish. If she keeps two-inch fish in the second tank and three-inch fish in the first tank, how many more fish would Gail have in the first tank than the second tank if one of the first tank fish eats another? Let's think step by step and output the final answer after "####".
user
The second tank is 48 / 2 = <<48/2=24>>24 gallons.
Following her rule, Gail keeps 24 / 2 = <<24/2=12>>12 two-inch fish in the second tank.
She keeps 48 / 3 = <<48/3=16>>16 fish in the first tank.
If one fish in the first tank ate another, she would have 16 - 1 = <<16-1=15>>15 fish in the first tank.
Thus, Gail would have 15 - 12 = <<15-12=3>>3 more fish in the first tank.
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Gail has two fish tanks. The first tank is twice the size of the second tank. There are 48 gallons of water in the first tank. She follows the rule of one gallon of water per inch of fish. If she keeps two-inch fish in the second tank and three-inch fish in the first tank, how many more fish would Gail have in the first tank than the second tank if one of the first tank fish eats another?
train