A father and a son start approaching each other at the same time from opposite ends of a hallway that is 16m long. If the father is walking three times as fast as the son, at what distance from the father's end of the hallway will they meet? Let's think step by step and output the final answer after "####".
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Since the father is walking 3 times as fast as his son, their speeds are in a ratio of 3:1 respectively
They started at the same time so they will cover distance at the same ratio of 3:1
Each portion of the distance they covered is 16/(3+1) = <<16/(3+1)=4>>4m
The father covered three portions of the distance which is 3*4m = <<3*4=12>>12m from his end
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A father and a son start approaching each other at the same time from opposite ends of a hallway that is 16m long. If the father is walking three times as fast as the son, at what distance from the father's end of the hallway will they meet?
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