A group of hawks is called a kettle. It is breeding season for hawks. A group of ornithologists are tracking 6 kettles of hawks. Each kettle has an average of 15 pregnancies that yield 4 babies per batch.  How many babies are expected this season if approximately 25% are lost? Let's think step by step and output the final answer after "####".
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Each kettle has 15 hawks that get pregnant and each one yields 4 babies per pregnancy so there are 15 * 4= <<15*4=60>>60 babies expected per kettle.
If 60 baby hawks are expected per kettle and the ornithologists are tracking 6 kettles total then there are 60 * 6=<<60*6=360>>360 baby hawks expected across all six kettles this breeding season.
If there 25% of eggs do not hatch, then we are looking for 25 (percent that do not make it) /100 (total number of babies expected)=<<25/100=.25>>.25 (percentage converted to decimal form for the proportion of expected baby hawks to be lost).
The total number of baby hawks expected equals 360 * .25 expected los s= <<360*.25=90>>90 babies not expected to hatch (lost).
There are 360 total number of baby hawks expected and there are 90 babies expected to be lost so 360-90= <<360-90=270>>270 remaining baby hawks expected this breeding season
#### 270
A group of hawks is called a kettle. It is breeding season for hawks. A group of ornithologists are tracking 6 kettles of hawks. Each kettle has an average of 15 pregnancies that yield 4 babies per batch.  How many babies are expected this season if approximately 25% are lost?
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