Santana has 7 brothers. 3 of them have birthdays in March, 1 of them has a birthday in October, 1 has a birthday in November, and another 2 of them were born in December. If Santana always buys each of her brothers a birthday present and a Christmas present, how many more presents does she have to buy in the second half of the year than the first half of the year? Let's think step by step and output the final answer after "####".
user
Santana has 1 + 1 + 2 = <<1+1+2=4>>4 brothers with birthdays in the second half of the year.
She has 7 brothers - 4 brothers = <<7-4=3>>3 brothers with birthdays in the first half of the year.
Altogether, she has to buy 4 + 7 = <<4+7=11>>11 presents in the second half of the year.
Therefore, she has to buy 11 - 3 = <<11-3=8>>8 more presents in the second half of the year.
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Santana has 7 brothers. 3 of them have birthdays in March, 1 of them has a birthday in October, 1 has a birthday in November, and another 2 of them were born in December. If Santana always buys each of her brothers a birthday present and a Christmas present, how many more presents does she have to buy in the second half of the year than the first half of the year?
train