A tank can hold 100 liters of water. At the beginning of the rainy season, the tank is 2/5 filled with water. On the first day of the rainy season, the tank collected 15 liters of water. On the second day, 5 liters more water was collected than on the first day. On the third day, the tank was already filled. How many liters of water were collected on the third day? Let's think step by step and output the final answer after "####".
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At the beginning of the rainy season, the tank is filled with 100 x 2/5 = <<100*2/5=40>>40 liters of water.
On the first day of the rainy season, the tank had 40 + 15 = <<40+15=55>>55 liters of water.
On the second day, 15 + 5 = <<15+5=20>>20 liters of water were collected.
So, the tank is filled with 55 + 20 = <<55+20=75>>75 liters of water on the second day.
Therefore, 100 - 75 = <<100-75=25>>25 liters of water were collected on the third day.
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A tank can hold 100 liters of water. At the beginning of the rainy season, the tank is 2/5 filled with water. On the first day of the rainy season, the tank collected 15 liters of water. On the second day, 5 liters more water was collected than on the first day. On the third day, the tank was already filled. How many liters of water were collected on the third day?
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