A bear eats up to 90 pounds of food per day to prepare for hibernation. If Victor weighs 126 pounds, how many "Victors" worth of food would a bear eat in 3 weeks? Let's think step by step and output the final answer after "####".
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There are 3 x 7 = <<3*7=21>>21 days in 3 weeks.
In 3 weeks, a bear would eat 90 x 21 = <<90*21=1890>>1890 pounds of food.
A bear would eat 1890/126 = <<1890/126=15>>15 "Victors" worth of food in 3 weeks.
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A bear eats up to 90 pounds of food per day to prepare for hibernation. If Victor weighs 126 pounds, how many "Victors" worth of food would a bear eat in 3 weeks?
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